The Keynesian cross takes investment as given. But investment falls when borrowing gets dearer, so every interest rate gives a different equilibrium income. Plot those pairs and you have the IS curve, half of the model that the rest of this module is built on.
In the Keynesian cross, output is autonomous spending times the multiplier. Investment sat inside autonomous spending as a fixed number. But the investment lesson of the foundations module showed that a firm invests in a project only if its return beats the cost of borrowing. When the interest rate rises, fewer projects pass, and investment falls. What matters is the real interest rate, the cost of borrowing after inflation (UGC NET 2023).
The simplest way to write it is a straight line:
Output depends on investment, and investment depends on the interest rate, so output now depends on the interest rate. The IS curve is that relationship. Its name says what holds along it: planned Investment equals Saving, which is the same as saying that planned spending equals output. It is the set of combinations of income and the interest rate at which the goods market is in equilibrium (CUET 2021; Hyderabad 2012).
Pick an interest rate. Investment is I₀ − br, so planned spending is a line in the Keynesian cross; where it crosses the 45° line is equilibrium output. Raise the interest rate and investment falls, the spending line shifts down, and output falls by b times the multiplier for every point. Mark each (Y, r) pair on a second diagram: the points line up into a downward-sloping curve. That is IS.
r = 6% → investment is lower by b·r = 120 → autonomous spending 280 → output 280 ÷ (1 − 0.75) = 1,120.
IS: Y = 4 × (400 − 20r). One point off r moves output by b/(1 − c) = 80, so the slope is dr/dY = −(1 − c)/b = −0.0125.
Put the investment function into the goods-market equilibrium and solve for Y exactly as in the cross. With a proportional tax, consumption is C₀ + c(1 − t)Y:
If investment also rises with income, I = I₀ + dY − br, the spending line gets steeper and the multiplier becomes 1/(1 − c − d). DSE 2006 had C = 2,000 + 0.4Yd, T = 1,000, G = 400 and I = 500 − 10r + 0.4Y: then 0.2Y = 2,500 − 10r and IS is Y = 12,500 − 50r.
A fall of one point in the interest rate raises investment by b, and output by α·b. The bigger that response, the flatter IS, because a small change in r moves Y a long way. So IS is flatter when:
In the extreme, if investment ignores the interest rate (b = 0), output doesn’t depend on r at all and IS is vertical (JNU 2018, Hyderabad 2018). Lesson 5 shows why monetary policy then has no effect.
A general version (CUET 2023): if demand is A(Y, r) and IS is the set of points with Y = A(Y, r), differentiating gives dY = AYdY + Ardr, so along IS dY/dr = Ar/(1 − AY).
A change in the interest rate is a movement along IS (Hyderabad 2010). Anything else that changes spending at a given interest rate shifts the whole curve, by the change in autonomous spending times α:
Take a point to the right of IS. Income there is higher than the goods market can support at that interest rate: output exceeds planned spending, and there is an excess supply of goods. To the left of IS, spending exceeds output: an excess demand for goods, stocks run down and firms raise output. Lesson 4 pairs this with the same idea for the money market to see how the economy finds its way back.
Definitions, directions of shifts and one-step problems. Most CUET, UGC NET and Hyderabad questions sit here.
Solving models, comparing slopes and multi-step reasoning, up to the hardest JNU, JAM and GATE questions.
This topic’s hardest questions, from the DSE entrance, are worked through in Lesson 10: IS–LM in letters.
These are questions from the TestStop bank. A free account answers 10 a day, each with its worked solution; All-Access opens every set with no daily limit.