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Resources › Statistical inference › 13. Hard problems
Statistical inference · Lesson 13 of 13

The hard problems

The Delhi School entrance asks inference questions with very little to compute and a lot to see. A table with two missing entries, a sample of two from an urn of three, one observation from one of two densities. The arithmetic is short once you have chosen the right object. This lesson goes through the techniques, with a worked question for each, then collects every DSE inference question above the easy level, 24 in all, in six sets.

← Statistical inference moduleLesson 13 of 13 · about 45 minutes
1Joint distributions2Sampling3CLT4Estimators5Likelihood6Intervals7Testing8Tests in practice9Two samples10Chi-square tests11ANOVA12Regression inference13Hard problems
A question to hold on to
A sample of size 2 is drawn without replacement from an urn with balls numbered 1, 2 and 3. X is the smaller number drawn and Y the larger. Find the covariance between X and Y.
Delhi School 2015Solved at the end ↓
In this guide
Lesson · about 45 minutes
  1. How the Delhi School writes inference questions
  2. Joint tables: unknowns, margins and small samples
  3. Sampling and the standard error
  4. Estimation and intervals: read the claim
  5. Errors and power: which density, which area
  6. Tests: compute, then compare
  7. Regression: what an assumption buys
  8. Which technique?
  9. The lesson on one screen
  10. Check yourself
  11. The DSE sets
01
Before any formula

How the Delhi School writes inference questions

The ordinary exams ask what a procedure is. A hard DSE question asks you to run it on a small, odd case, and the odd case is the point: it is chosen so that the general result would be a trap. Four habits cover most of them.

  1. Write the whole distribution down. When the sample space is small, list it. Three balls, two draws, three equally likely outcomes: you need no theory, only a table.
  2. Simplify before you compute. A variable that takes the values ±1 is its own reciprocal. A sum of identical terms is twice one of them.
  3. Ask which distribution you are under. Size is computed under H₀, β and power under H₁, a standard error under the null for a test and with estimates for an interval.
  4. Read each option as a claim and test it. Several options are true statements about the wrong thing. Take each to an extreme case or a specific number.

Every worked question below is a real DSE paper question.

02
Part 1

Joint tables: unknowns, margins and small samples

Four ideas from Lesson 1 account for every question in this set: a table’s cells add to 1, marginals come from adding along an edge, E(X) and E(Y) are linear in the cells, and covariance is E[XY] − E[X]E[Y]. The unknown-entries questions (DSE 2011, 2017) are solved in the lesson itself. Two others need a different idea.

DSE 2007 · moderate
The marginal probabilities of age A are P(15) = 0.06, P(25) = 0.38, P(40) = 0.33, P(60) = 0.22 and P(80) = 0.01. Find the expectation of A.
  1. 1
    The marginal is all you need.
    The question also gives the joint distribution of age and the weight lifted, but E(A) depends on the marginal of A only.
  2. 2
    Weighted sum.
    15 × 0.06 + 25 × 0.38 + 40 × 0.33 + 60 × 0.22 + 80 × 0.01 = 0.9 + 9.5 + 13.2 + 13.2 + 0.8 = 37.6.
Answer
37.6 years. The question hands you extra material (the joint table) to see whether you spot you do not need it.
DSE 2015 · moderate
Draw two balls without replacement from an urn numbered 1, 2, 3. X is the smaller, Y the larger. Find Cov(X, Y).
  1. 1
    List the equally likely samples.
    (1, 2), (1, 3), (2, 3), each with probability 1/3, giving (X, Y) = (1, 2), (1, 3), (2, 3).
  2. 2
    Expectations.
    E[X] = (1 + 1 + 2) ÷ 3 = 4/3. E[Y] = (2 + 3 + 3) ÷ 3 = 8/3. E[XY] = (2 + 3 + 6) ÷ 3 = 11/3.
  3. 3
    Covariance.
    11/3 − (4/3)(8/3) = 33/9 − 32/9 = 1/9.
Answer
1/9: option A. The covariance is positive because a larger smaller-ball tends to go with a larger larger-ball, and the numbers are so small that a direct list is faster than any formula. The other options are not what the three-line list gives.
DSE 2016 · hard
X is normal with mean 0 and variance σ². Y takes the values −1 and 1 with equal probability, independently of X. Z = XY + X/Y. Compare Var(Z) with σ².
  1. 1
    Simplify.
    Since Y = ±1, 1/Y = Y. So Z = XY + XY = 2XY.
  2. 2
    The distribution of XY.
    Given Y, XY is either X or −X, and X is symmetric about 0, so XY has the same normal distribution as X: mean 0, variance σ².
  3. 3
    Variance.
    Var(Z) = Var(2XY) = 4σ².
Answer
Var(Z) = 4σ², greater than σ²: option A. The trap is to add Var(XY) and Var(X/Y) as σ² + σ² = 2σ² as if they were independent. They are the same variable, and variances of identical terms add after doubling, as 2² σ².
03
Part 2

Sampling and the standard error

Two questions test whether you know what the sample proportion and mean actually are. Both are covered in Lesson 3, and the answers repay a second look.

DSE 2007 · moderate
In a survey of 400 likely voters, 215 say they will vote for the ruling party. What is the standard error of p̂?
  1. 1
    Estimate.
    p̂ = 215 ÷ 400 = 0.5375.
  2. 2
    Plug into √(p̂(1 − p̂) ÷ n).
    √(0.5375 × 0.4625 ÷ 400) = √0.000621 = 0.0249.
Answer
0.025: option A. If you use p = 0.5 you get √(0.25 ÷ 400) = 0.025 too. They agree here because 0.5375 is near a half, which is where p(1 − p) is largest.
DSE 2019 · moderate
X is the number of successes in a sequence of independent trials, each with probability p. X̄ is the mean number of successes. Which is true of X̄?
  1. 1
    Which theorem?
    X̄ is a mean of independent identically distributed variables with mean p and finite variance. The central limit theorem applies.
  2. 2
    Read the wording.
    The theorem says X̄ is approximately normal for large n. It is not exactly normal: a mean of 0-1 variables takes only finitely many values, so it is discrete. And it is not binomial itself, because it is a mean, not a sum.
Answer
X̄ approximates a normal distribution with mean p: option A. The word “approximates” is the whole question. The option that says it has a normal distribution is the trap.
04
Part 3

Estimation and intervals: read the claim

Six questions in this set are conceptual statements about estimates and intervals, and all but one are decided by reading each claim literally. The techniques are in Lessons 5 and 6, and the pattern is short.

  • A confidence interval is a statement about the procedure. Any option saying the interval contains β “with probability 0.95” is false (DSE 2010, 2016). The option that says “in repeated sampling 95% of intervals contain the true value” is true.
  • To shorten an interval, shrink the standard error or the confidence level, as a multiplier. Compare the factors: s ÷ 3 beats n × 4 (a factor of ½) beats a drop in confidence from 90% to 80% (a factor of 0.78) (DSE 2008).
  • Check an interval by arithmetic. σ = 2, n = 25, mean 10: the 95% interval is 9.22 to 10.78, so 9.3, 9.8 and 10.6 all lie inside (DSE 2012).
  • The interval for a variance divides (n − 1)S² by chi-square points, the larger one first for the lower limit (DSE 2012). Options with n in place of n − 1, or with the points swapped, fail.
  • One Bernoulli draw gives a maximum likelihood estimate of 0 or 1, never strictly between (DSE 2019).
05
Part 4

Errors and power: which density, which area

The test of one observation (DSE 2012) is the template: size under H₀ fixes the cut-off, β is the other density over the acceptance region. Two others in this set are shorter.

  • A diagnostic test for a rare disease, with the null that the patient is healthy. The mistake to avoid, calling a sick patient healthy, is failing to reject a false null: a Type II error, a false negative (DSE 2011).
DSE 2015 · moderate
In Y = a + b₁X₁ + b₂X₂ + u (large sample), t₁ and t₂ test b₁ = 0 and b₂ = 0, and are treated as independent. The joint null b₁ = b₂ = 0 is rejected if either |t₁| or |t₂| exceeds 1.96. What is the probability of Type I error?
  1. 1
    Each test alone.
    Under the null P(|t| > 1.96) = 0.05, so P(|t| ≤ 1.96) = 0.95.
  2. 2
    The joint rule does not reject only if both stay inside.
    By independence that is 0.95 × 0.95 = 0.9025.
  3. 3
    So it rejects with probability.
    1 − 0.9025 = 0.0975.
Answer
More than 5 percent: option C. This is the multiple-testing problem in miniature: combine tests at 5% each and the rule’s false-alarm rate is 9.75%. The fix is a joint test, such as the F test, built so that its own size is 5%.
06
Part 5

Tests: compute, then compare

Four questions ask you to compute a statistic and compare it with a critical value, and Lessons 8 and 9 solve three of them. The fourth has a feature worth seeing: four of its options are statements, and one of them must be picked out by reasoning rather than computing every probability.

DSE 2008 · hard
A sample of 1,000 mangoes has mean weight 210 g and standard deviation 9.5 g. Another sample of 1,200 has mean 180 g and standard deviation 11.5 g. Assume equal variances and H₀: μ₁ − μ₂ = 0. Which statement is true? (A) For H_A: μ₁ − μ₂ ≠ 0, reject the null at the 15%, 13%, 12% and 8% levels. (B) Do not reject at 1%. (C) The appropriate estimator is μ₁ − μ₂. (D) A test at the 7% level has a Type I error probability of 0.035.
  1. 1
    Compute the statistic.
    Pooled variance = (999 × 90.25 + 1,199 × 132.25) ÷ 2,198 = 113.2, so s = 10.64. Standard error = 10.64 × √(1/1000 + 1/1200) = 0.456. z ≈ 30 ÷ 0.456 = 66.
  2. 2
    (A).
    A statistic of 66 has a p-value that is essentially zero, so it rejects at every level, including those four. True.
  3. 3
    (B).
    Not rejecting at 1% is false for the same reason.
  4. 4
    (C) and (D).
    μ₁ − μ₂ is a parameter, not an estimator. The estimator is x̄₁ − x̄₂. And a test at the 7% level has Type I error probability 0.07, not 0.035. Both false.
Answer
(A). When a statistic is that large, every option that depends on a threshold is decided without a table, and the options about definitions are decided by reading them carefully.

The two-class comparison (z = −2.49: significant at 5%, not at 1%), the two district polls (not different, yet one candidate is preferred in one district) and the claimed income with a known variance (z = −1.36, not rejected) are worked in Lesson 9 and Lesson 8.

07
Part 6

Regression: what an assumption buys

Two questions from 2009 ask the same thing in two ways: given the four standard assumptions on the errors of a simple regression, which ones do you need for a particular property? The skill is to tie each property to the argument that proves it, which Lesson 12 gives.

DSE 2009 · moderate
Least squares fits y = β₁ + β₂x + ε. The assumptions are (1) E(ε) = 0, (2) Cov(x, ε) = 0, (3) Var(ε) = σ² for every observation, (4) Cov(εᵢ, εⱼ) = 0 for i ≠ j. When are the least-squares estimators unbiased? When are they the best unbiased estimators?
  1. 1
    Write the slope as a weighted sum of the y's.
    b = Σwᵢyᵢ with weights wᵢ = (xᵢ − x̄) ÷ Sxx, which sum to 0 and satisfy Σwᵢxᵢ = 1.
  2. 2
    Take the expectation.
    E(b) = Σwᵢ(β₁ + β₂xᵢ + E εᵢ) = β₂ whenever the errors average zero and are not related to x. Only (1) and (2) were used.
  3. 3
    Now the variance.
    Var(b) = σ²Σwᵢ² needs the errors to share one variance and to be uncorrelated, so (3) and (4) enter. The Gauss-Markov theorem says that under all four, no linear unbiased estimator has a smaller variance.
Answer
Unbiased: only if (1) and (2) hold, option A. Best: only if all four hold, option B. Violating (3) or (4) leaves the estimates unbiased but not best, and makes the usual standard errors wrong.
08
Drill

Which technique?

In the exam the hardest step is the first: seeing which of the techniques above the question is inviting. Six situations; pick the opening move.

Which technique? · 1 of 6
A joint table has two unknown entries, a and b, and you are told E(X) and E(Y).
The pattern

Each question here is a single idea in disguise: list a tiny sample space, simplify before computing, use the right density for the right error, and read a test statement as a number you can compare. The difficulty is almost always in noticing the idea, not in the arithmetic.

Watch out for

The mistakes examiners are fishing for

  • Adding variances of terms that are not independent. XY and X/Y are the same variable when Y = ±1.
  • Computing β under the null. β uses the alternative density, over the acceptance region.
  • Using a formula where the sample space is tiny. Two draws from three balls: list them.
  • “Has” against “approximates”. The central limit theorem gives an approximation.
  • Reading an interval as a probability statement about the parameter.
09
Revise

The lesson on one screen

The lesson on one screen
Joint tables
Cells add to 1. E(X) and E(Y) are linear in the cells. E(A) needs only A's marginal. Small samples without replacement: list the equally likely outcomes.
Simplify first
If Y = ±1 then 1/Y = Y. Identical terms double, they do not add as independent ones.
Standard errors
SE(p̂) = √(p̂(1 − p̂)/n). The sample mean of Bernoulli trials is approximately normal, not exactly.
Intervals
95% describes the procedure. Shorten by a smaller s, a bigger n or lower confidence. Variance interval: (n − 1)S² over χ² points, larger point for the lower limit.
Errors and power
Size under H₀ fixes k. β under H₁ over the acceptance region. Failing to flag the sick is Type II. Two tests at 5% each: 1 − 0.95² = 0.0975.
Regression
Unbiased needs zero mean and no correlation with x. Right standard errors also need constant variance and no autocorrelation. Best (BLUE) needs all four.
Tests
(estimate − null) ÷ SE. 1.96 to 2.58: reject at 5%, not at 1%. Pooled proportions for a difference; the null value for a single proportion.
10
Practice

Check yourself

0 of 13 correct so far

Compute

Smaller and larger of two draws
Two balls are drawn without replacement from an urn numbered 1, 2, 3, 4. X is the smaller and Y the larger. Find Cov(X, Y).
Simplify, then take the variance
X has variance 9. Y is −1 or 1 with equal chance, independent of X. Find Var(XY + X/Y).
Two unknown entries
X is 0 or 1 and Y is 1 or 2. The joint probabilities are: X = 0 with Y = 1: 0.2, with Y = 2: a. X = 1 with Y = 1: b, with Y = 2: 0.3. Given E(Y) = 1.6, find a.
A marginal expectation
The marginal distribution of age is: 20 with probability 0.2, 30 with 0.5 and 50 with 0.3. Find the expected age.
A standard error
56% of 300 voters back a candidate. Find the standard error of the sample proportion.
Size and β from one observation
H₀: f(x) = 3x² and H₁: f(x) = 1, both on [0, 1]. The test rejects H₀ if x < k, with α = 0.027. Find β.
Several tests at once
Four independent tests are each run at 5%, and H₀ is rejected if any one rejects. Find the probability of a false rejection when all the nulls are true.
A t statistic from sums
A sample of n = 9 has Σx = 54 and Σx² = 400. Find the t statistic for H₀: μ = 5.

Quick questions

1Y is −1 or 1 with equal probability. Then XY and X/Y are
2The standard error of a sample proportion is largest, for fixed n, when p is
3In a test of one observation with a rule such as 'reject H₀ if x < k', the size is computed under
4A joint table has two unknown entries. Total probability and E(X) are given. How many equations do you have?
5Two independent tests at 5% each, joint rule 'reject if either rejects'. The size of the joint rule is
11
Real questions

The DSE sets

Every DSE inference question above the easy level, in the order of this lesson. Within each set, moderate questions come first, then hard ones. The easy DSE questions are in the lessons for their topic.

Part 1 · from Lesson 1

Joint distributions

Normalising a joint table, conditioning, covariance from a table, and the variance of a sum.

7 questionsPractise →
Part 2 · from Lessons 2 and 3

Sampling and the standard error

The standard error of a mean and the central limit theorem at the Delhi School's level.

2 questionsPractise →
Part 3 · from Lessons 4 and 5 and 6

Estimation and confidence intervals

The maximum likelihood estimate from a single draw, what a confidence interval does and does not say, how its width responds, and the interval for a variance.

6 questionsPractise →
Part 4 · from Lesson 7

Errors, power and the test of a single observation

Which error a doctor must keep small, the false-alarm rate of two tests run together, and the size and power of a test built on one observation.

3 questionsPractise →
Part 5 · from Lessons 8 and 9 and 10

Tests on means and proportions

Comparing two class means, two district polls, two mango samples, and a claimed mean with a known variance.

4 questionsPractise →
Part 6 · from Lesson 12

Regression: what an assumption buys

Which assumptions make the least-squares estimators unbiased, and which make them best.

2 questionsPractise →
All 24 DSE questions, moderate before hard within each part: practise the full set →

✦These are questions from the TestStop bank. A free account answers 10 a day, each with its worked solution; All-Access opens every set with no daily limit.

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