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Resources › General equilibrium and welfare › 5. Social choice
General equilibrium and welfare · Lesson 5 of 6

Social welfare, compensation and Arrow's theorem

Efficiency leaves a lot open: the contract curve has many points, and moving along it makes one person better off and another worse. To rank them we need a value judgement. This lesson covers the standard ways economists make one, what they can and cannot do, and why no voting rule escapes all the paradoxes.

← General equilibrium and welfare moduleLesson 5 of 6 · about 45 minutes
1The box2Equilibrium3Production4Welfare theorems5Social choice6Delhi School
A question to hold on to
200 kg of food must be shared between two sailors on an island. Their utilities are u₁ = √F₁ and u₂ = ½√F₂, where Fi is the food sailor i eats. The social welfare function is w = √u₁ · √u₂. How should the food be allocated to maximise social welfare? (A) 200, 200 (B) 140, 70 (C) 100, 100 (D) None of the above.
JNU 2020 (Economics)Solved at the end ↓
In this guide
Lesson · about 45 minutes
  1. From efficient to best: the utility frontier
  2. Social welfare functions
  3. Compensation tests
  4. Who said what, and when
  5. Fairness as no envy
  6. Voting and Arrow's theorem
  7. The opening question, solved
  8. The lesson on one screen
  9. Check yourself
  10. Past papers, by level
01
The setting

From efficient to best: the utility frontier

Take the contract curve of Lesson 1 and measure each person on it by her utility instead of her bundle. The result is the utility possibility frontier: every efficient split of utility between two people. It shows, in utility terms, all the efficient allocations (CUET 2026). The contract curve, the utility possibility frontier and the production possibility frontier are three different objects, and the matching question in CUET 2026 asks you to tell them apart: the contract curve shows efficient allocations of goods; the frontier shows efficient allocations in terms of utility; the PPF shows the combinations of two goods that can be made with given inputs.

Every point on the frontier is Pareto efficient, so the Pareto criterion cannot choose among them. Going from one to another helps one person and hurts the other, and the Pareto criterion is silent. Choosing needs a social welfare function (JNU 2016): it ranks every feasible allocation, which the Pareto criterion cannot.

02
Value judgements

Social welfare functions

A Bergson–Samuelson social welfare function turns everyone’s utility into one number for society: W = f(U₁, …, Um). Abram Bergson introduced the idea in 1938; Paul Samuelson developed it in 1947. Three standard forms (JAM 2026):

Welfare functionFormulaValue judgementIts level curves
Utilitarian (Bentham, Mill)W=∑i​Ui​, or with weightsOnly the total matters; who has it does notStraight lines
Rawlsian (maximin)W=mini​Ui​Only the worst-off person counts (John Rawls, A Theory of Justice, 1971)L-shapes with corners on the 45° line
Nash (product)W=∏i​Ui​Dislikes inequality of utilities, but not as sharply as maximinHyperbolas

Two traps in JAM 2026. Rawls’s function is the minimum of utilities, not the maximum. And a social welfare function reflects value judgements; interpersonal comparisons of utility cannot be made “on scientific grounds”. The lab draws the level curve of each function that just touches the frontier, which is the planner’s choice.

Sailor 1's utility is √F₁ and sailor 2's is ½√F₂: the second gets less from each kilo. Sharing 200 kg, every split is efficient.

Adds utilities: W = w·u₁ + (1 − w)·u₂. With equal weights this is Bentham's sum.

24681012141234567u₁u₂
Utility possibility frontierLevel curve of W through the choice┄ equal utilities
The planner’s choice

Utilities (12.65, 3.16): sailor 1 eats 160 kg, sailor 2 eats 40 kg.

What it shows

The level curve is a straight line of slope −1. The choice is where the frontier has that slope: a larger weight on person 1 moves it toward person 1.

Pause and predict
On the sailors' frontier, a Rawlsian planner gives the sailor who gets less from each kilo
03
Potential Pareto improvements

Compensation tests

Most policies create winners and losers, so the Pareto criterion often says nothing. The compensation principle (JNU 2019) asks a different question: could the winners compensate the losers? The compensation need not actually be paid. Three tests, in order:

  • Kaldor criterion (1939): the change is an improvement if the gainers could pay the losers enough to make them as well off as before and still be better off themselves.
  • Hicks criterion (1939): the change is an improvement if the losers could not profitably pay the gainers to give it up.
  • Scitovsky double criterion (1941): the move must pass the Kaldor test and the move back must fail it (the “reversal test”). Together this is what UGC NET calls a double Kaldor–Hicks test (UGC NET Dec 2024, JNU 2019).

Why a double test? The Kaldor test alone can approve a move and also approve the move back. That is the Scitovsky paradox, and it happens when the utility possibility frontiers cross: each position can compensate its way to the other. Use the lab below to see both.

24681012141624681012u₁u₂ab
Old frontier ANew frontier BBeats a for everyoneBeats b for everyone
The move from a to b

Person 1 loses 1.16 and person 2 gains 1.06. There is a loser, so the Pareto criterion is silent; the compensation tests are what is left.

Kaldor passes

The new frontier has a point north-east of a (the shaded gold area): the winners could pay the losers and everyone would be better off than at a.

Hicks fails

The old frontier does reach the red area north-east of b: staying put and redistributing could have beaten b for everyone.

The Scitovsky paradox

Kaldor passes for the move from a to b and also for the move back from b to a: the frontiers cross, and each position can 'compensate its way' to the other. The Kaldor test alone approves both directions. Scitovsky's reversal test rules this out.

What the criteria are, and are not

The compensation tests ask about a potential Pareto improvement; compensation is hypothetical. They ignore who the winners and losers are, so a rich man’s gain can outweigh a poor man’s loss. The welfare criterion based on compensation payments is the Kaldor–Hicks criterion (UGC NET Dec 2025).

04
Dates

Who said what, and when

Exams ask you to match these or put them in order, so learn the sequence. The dates below are from the original publications.

YearContributionWho
1906–09Pareto optimality criterion (Manuale di economia politica, 1906; the French edition followed in 1909)Pareto
1938The social welfare function, in “A Reformulation of Certain Aspects of Welfare Economics”Bergson
1939Compensation criterion (Kaldor in the Economic Journal, Hicks in the same journal later that year)Kaldor; Hicks
1941The double criterion and the reversal testScitovsky
1950–51Impossibility theorem: “A Difficulty in the Concept of Social Welfare” (1950), then Social Choice and Individual Values (1951)Arrow
1971Principle of social justice, maximin (A Theory of Justice)Rawls

So CUET 2025’s chronology, oldest first, is Pareto, Bergson, Kaldor–Hicks, Rawls. The matching question in JNU 2019 pairs a double Kaldor–Hicks test with Scitovsky, the compensation principle with Kaldor–Hicks, a social welfare function with Bergson, and the impossibility theorem with Arrow.

A key we think is wrong

UGC NET June 2026 asked for Pareto, Bergson, Kaldor–Hicks and Bentham from latest to earliest and keys Bergson as the latest. Bergson’s paper is from 1938 and Kaldor’s and Hicks’s are from 1939, which CUET 2025 also reflects, so the correct order is Kaldor–Hicks, Bergson, Pareto, Bentham. We have left that question out of the practice sets.

05
Fairness

Fairness as no envy

A different test of a fair allocation needs no welfare function. An allocation is envy-free (a no-envy allocation) if nobody prefers someone else’s bundle to her own. Giving a cake of 1 kg half to each of two people who like cake is both efficient and envy-free (JNU 2017); giving the whole cake to one person is efficient but the other envies her; and (0.5, 0.4) is neither efficient (0.1 is wasted) nor envy-free. Efficiency and envy-freeness are different tests, and an allocation can pass one and fail the other.

06
Voting

Voting and Arrow's theorem

Suppose three voters rank three alternatives and we use majority rule. Try the lab’s first profile: each alternative is first for exactly one voter. A beats B, B beats C and C beats A, two votes to one each time. This is Condorcet’s voting paradox: majority rule can cycle, so it gives no ranking at all.

Each alternative is first for exactly one voter. A beats B, B beats C and C beats A, two votes to one every time.

Votes for the row over the columnABC
A–21
B1–2
C21–
Majority rule

A cycle: each alternative loses to another by two votes to one, so majority rule gives no ranking at all.

Other rules

Borda points: A 3, B 3, C 3. Maximin on rank (Rawls): A or B or C. Pareto optimal alternatives: A, B, C.

Kenneth Arrow asked whether any rule avoids this. His answer, first published in 1950 as “A Difficulty in the Concept of Social Welfare” and in 1951 in Social Choice and Individual Values, is that none does. With at least three alternatives, no way of combining individual rankings into a social ranking satisfies all of:

  • Unrestricted domain: it works for every possible set of individual rankings.
  • The Pareto principle: if everyone prefers A to B, so does society.
  • Independence of irrelevant alternatives: society’s ranking of A and B depends only on how individuals rank A and B.
  • Non-dictatorship: no single individual’s preference decides everything.

Any rule that satisfies the first three has a dictator. The essence of the theorem is that no collective decision rule can guarantee results that are not unfair or paradoxical (Hyderabad 2010), not that efficiency is impossible, nor that collective action is impossible.

Watch out for

The mistakes examiners are fishing for

  • Rawls = maximum. It is the minimum (maximin).
  • Kaldor–Hicks means someone must be paid. It is a potential compensation test.
  • Bergson and Kaldor in the wrong order. Bergson 1938, Kaldor and Hicks 1939, Scitovsky 1941.
  • Arrow says efficiency is impossible. It says no rule satisfies all of his conditions at once. Pareto efficiency is one of the conditions.
  • Level curves. Utilitarian: straight lines; Rawls: L-shaped; Nash: hyperbolas.
07
Worked questions

The opening question, solved

JNU 2020 · advanced
200 kg, u₁ = √F₁, u₂ = ½√F₂, w = √u₁·√u₂. Find the welfare-maximising split.
  1. 1
    Write w in terms of food.
    w = u₁½·u₂½ = (F₁½)½·(½F₂½)½ = (1/√2)·F₁¼·F₂¼.
  2. 2
    Maximise a product with a fixed sum.
    F₁¼F₂¼ is largest when F₁ = F₂ (the exponents are equal), so F₁ = F₂ = 100.
Answer
100 kg each (option C). The ½ in sailor 2’s utility drops out because it multiplies the product by a constant.
JAM 2026 · standard
Which is correct about a social welfare function SWF = f(U₁, …, Um)? (A) Bentham and Mill proposed Σ wiUi with distinct weights. (B) Interpersonal comparisons can be made on scientific grounds. (C) Rawls proposed SWF = max Ui. (D) If SWF = ΣUi, it is the utilitarian function.
  1. 1
    A.
    Bentham and Mill gave everyone an equal weight, which is what ΣUi means.
  2. 2
    B.
    A welfare function is a value judgement; interpersonal comparisons are not scientific.
  3. 3
    C.
    Rawls’s function is the minimum.
Answer
D.
UGC NET 2024 · advanced
Scitovsky double criterion: (A) does not require Kaldor–Hicks; (B) requires only the reversal test; (C) does not require the reversal test; (D) requires the Kaldor–Hicks test and the reversal test.
  1. 1
    Recall.
    Scitovsky added a reversal test to the Kaldor test so that a move cannot be approved in both directions.
Answer
D.
CUET 2025 · advanced
Order from oldest to latest: (A) Kaldor–Hicks compensation criterion, (B) Bergson social welfare function, (C) Rawls’s principle of social justice, (D) Pareto optimality criterion.
  1. 1
    Use the dates.
    Pareto 1906, Bergson 1938, Kaldor–Hicks 1939, Rawls 1971.
Answer
D, B, A, C (option D).
08
Revise

The lesson on one screen

The lesson on one screen
Utility possibility frontier
Efficient splits of utility: the contract curve in utility terms. The Pareto criterion cannot choose among its points.
Social welfare function
Ranks all allocations. Bergson 1938, Samuelson 1947. Needs a value judgement.
Forms
Utilitarian Σ U (straight level curves); Rawls min U (L-shaped); Nash Π U (hyperbolas).
Kaldor
Gainers could compensate losers and still gain. Hypothetical.
Hicks
Losers could not bribe the gainers to forgo the change.
Scitovsky
Kaldor passes forward and fails backward. Catches the paradox when frontiers cross.
Envy-free
Nobody prefers another's bundle. A different test from efficiency.
Arrow
No rule with unrestricted domain, Pareto, IIA and no dictator, for 3+ alternatives. Majority rule cycles.
09
Practice

Check yourself

0 of 5 correct so far

Quick questions

1Which of these is not one of Arrow's conditions?
2A move makes gainers better off by up to ₹50 in total and losers worse off by ₹30. The Kaldor criterion
3The Scitovsky paradox arises when
4A Rawlsian planner maximises

Numerical problem

Rawlsian sharing
100 units of food are shared between two people. Person 1’s utility is F₁ and person 2’s is 2F₂. A Rawlsian planner maximises the smaller utility. How much food does person 1 get (to one decimal place)?
10
Real questions

Past papers, by level

Foundation

Definitions and who-said-what: Pareto efficiency, the contract curve, Walras' law and the welfare theorems. Most CUET, UGC NET and Hyderabad questions sit here.

1 questionPractise →

Standard

Statements to judge, matching lists, and equilibrium prices and bundles to compute with Cobb–Douglas and Leontief tastes, up to JAM, GATE and JNU level.

8 questionsPractise →

Delhi School level

This topic’s hardest questions, from the DSE entrance, are worked through in Lesson 6: Transfers, production and fairness.

7 questionsLesson 6 →
All 9 past-paper questions for this lesson, easiest first: practise the full set →

✦These are questions from the TestStop bank. A free account answers 10 a day, each with its worked solution; All-Access opens every set with no daily limit.

← Lesson 4The two welfare theoremsLesson 6 →The Delhi School economies

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