The Delhi School of Economics entrance asks the hardest econometrics questions of any Indian economics exam, and asks them in words and symbols rather than from data. A regression is rewritten, a coefficient is moved, a variable is added or left out, and you are asked what must be true. This lesson teaches the techniques behind them, then gives you every DSE question above the easy level, 28 in all, in seven sets.
You regress Y on X₁ and X₂ by OLS and get coefficients b₁ and b₂. You then regress Y on X₁ and X₁ + X₂, and get c₁ and c₂. Which is correct? (A) There is no need to run the second regression: c₁ and c₂ can be derived from b₁ and b₂. (B) The second regression is incorrect; it will not give an unbiased estimator. (C) It is better to run the first regression: its sum of squared residuals will be smaller. (D) The second regression is incorrect: its error term will be correlated with the regressors.
How the Delhi School writes econometrics questions
Questions in other exams ask for a number from a formula. The hard ones here ask what must be true, so the work is to find the right object and read off the answer. Almost all of them fall into seven families, and this lesson takes them in turn. Four habits run through all of them.
Rewrite, do not re-estimate. Most questions can be settled by writing one regression in terms of another. You need no data.
Find the quantity that is invariant. A fit does not change when the regressors are replaced by combinations of themselves; R², t ratios and F do not change when units change; the coefficients do.
Name the object the table gives you. A table of coefficients and standard errors hands you t ratios, adjusted R², standardised effects and, with a sample size, F.
Check the claim against the assumptions. “Which statement is false?” is usually a statement that is true only under an assumption the question has removed (an intercept, a constant error variance, uncorrelated regressors).
The earlier lessons taught the ideas. This one is about recognising them under a different cover, so each part begins with the disguise, then shows one question worked out. The right answer to each of the 28 questions is, in the end, a line or two.
02
Part 1
The algebra of least squares
The disguise: a statement about residuals, fitted values or a re-parametrised regression, with no numbers at all. The tools: the residuals are orthogonal to every regressor and sum to zero (with an intercept); Y = Ŷ + e splits Y into two uncorrelated pieces; the coefficients of a regression on combinations of the regressors are the same fit in different coordinates; and Var(bj) = σ² ÷ [SSTj(1 − Rj²)].
What moves the variance of one coefficient
Var(bj)=SSTj(1−Rj2)σ2
A smaller sample, less spread in x_j, a larger error variance and a higher correlation with the other regressors (R_j²) all raise the variance.
Delhi School 2021
Regress Y on X₁ and X₂ to get b₁ and b₂. Then regress Y on X₁ and X₁ + X₂ to get c₁ and c₂. Which statement is correct?
1
Write the first fitted equation.
Ŷ = b₁X₁ + b₂X₂ (plus the intercept, which plays no part here).
It is a linear function of the second regression’s regressors, and least squares gives the unique best linear function of them. So the fit is identical and c₁ = b₁ − b₂, c₂ = b₂. Both regressions have the same residuals, so options B, C and D (bias, a smaller sum of squares, a correlated error) all fail.
Answer
(A): c₁ and c₂ follow from b₁ and b₂ directly. The same logic is why the choice of base category for a set of dummies changes the coefficients but not the fit.
Delhi School 2016
Residuals e come from the regression of Y on a constant, X₂ and X₃. Which statement is false? (A) The R² of e on a constant, X₂ and X₃ is zero. (B) The R² of Y on a constant and Ŷ equals the original R². (C) The slope of Y on a constant and Ŷ is 1 and the intercept 0. (D) The R² of Y on a constant and e equals the original R².
1
Use Y = Ŷ + e.
The residuals are uncorrelated with every regressor, so (A) is true: nothing is left to explain. They are also uncorrelated with Ŷ, which is a combination of the regressors.
2
Regress Y on Ŷ.
Cov(Y, Ŷ) = Cov(Ŷ + e, Ŷ) = Var(Ŷ), so the slope is Var(Ŷ) ÷ Var(Ŷ) = 1, the intercept 0, and R² = Var(Ŷ) ÷ Var(Y), the original R². (B) and (C) are true.
3
Regress Y on e.
Cov(Y, e) = Var(e), so the R² is Var(e) ÷ Var(Y) = 1 − R²: the share of variation not explained. That equals the original R² only if R² = 0.5.
Answer
(D) is false. It gives 1 − R², not R². The other three follow from the orthogonality of residuals.
Watch out for
The mistakes examiners are fishing for
Using a formula without its assumption. In DSE 2012 Q31, a regression through the origin, the mean square error divides by n − 1 (one parameter), the residuals need not sum to zero, and R² is uncentred, so it can be high with low correlation. The formula with n Σ XY − Σ X Σ Y is the slope with an intercept, so that is the false statement.
Forgetting that every one of the four items moves the variance. In DSE 2018 Q20 each of a smaller sample, less variation in x₂, more error variance and a higher correlation with x₁ raises Var(b₂), so all four are right.
03
Part 2
Tests and fit from a regression table
The disguise: a regression printed with standard errors, an R², a sample size, and a question that needs one more step. The tools: t = b ÷ se against about 1.98 at 100 degrees of freedom; adjusted R² = 1 − (1 − R²)(n − 1) ÷ (n − k − 1); the F test for adding a variable from two residual sums of squares; a standardised effect b × sx ÷ sy; and the explained sum of squares of a dummy regression from the group sizes and the gap.
Delhi School 2018
A regression with three variables and 105 observations has residual sum of squares 300. Adding a fourth variable cuts it to 250. The 5% critical value of F(1, 100) is 3.89. Does the fit improve significantly?
1
One restriction, so one numerator degree.
Dropping the fourth variable is one restriction. The unrestricted model has an intercept and four slopes, so the denominator has 105 − 5 = 100 degrees of freedom.
20 is well above 3.89. (Equivalently, t = √20 = 4.5 for the fourth variable.)
Answer
(D) The fit improves significantly.
Delhi School 2015
In W = 300 − 50D + u, with D = 1 for women, there are 150 men and 50 women. Find the explained sum of squares.
1
Read the group means from the coefficients.
Men (D = 0) average 300 and women (D = 1) average 250, a gap of 50.
2
The regression fits the two means.
The grand mean is (150 × 300 + 50 × 250) ÷ 200 = 287.5. The explained sum of squares is the spread of the two means around it: 150 × 12.5² + 50 × 37.5² = 23,437.5 + 70,312.5 = 93,750.
(A) 93,750. The data are not needed, only the group sizes and the gap.
Other questions in this set: the home-sales table of DSE 2019 asks about both the significance of two coefficients (t = 23.4 ÷ 10.76 = 2.17 and 35.6 ÷ 10.5 = 3.39, both beyond 1.98: significant) and the adjusted R² (1 − 0.28 × 106 ÷ 100 = 0.7032). DSE 2016 Q12 asks for a standardised effect: 2.3 × 5 ÷ 500 = 0.023 standard deviations of birth weight. Lessons 3 and 4 teach each step.
04
Part 3
Dummy variables, recoding and kinks
The disguise: a gender gap, a dummy coded differently, two complementary dummies and no constant, a product of dummies, or a threshold in income. The tools: a dummy regression fits group means; a dummy’s coefficient is a gap that only means something given the rest of the equation; recoding a dummy is a change of variable you can substitute through; and the precision of a gap depends on the group sizes.
Delhi School 2018
y = 10 + 1.5x + 4D, with D = 0 for women and 1 for men. If the dummy were coded −1 for women and +1 for men, what would the estimated coefficients be?
Men: 12 + 2 = 14 = 10 + 4. Women: 12 − 2 = 10. The fitted lines are unchanged, only the labels moved.
Answer
(B) 12, 1.5, 2: the intercept moves to the midpoint of the two groups, the dummy coefficient halves, the slope on x is untouched.
Delhi School 2018
y = α + βx + γUrban + θImmigrant + δ(Urban × Immigrant). What is θ?
1
Write the immigrant gap in each setting.
Rural (Urban = 0): the Immigrant terms give θ. Urban (Urban = 1): they give θ + δ.
2
So θ is the gap where the interaction vanishes.
Only at Urban = 0.
Answer
(A) θ is the difference between a rural immigrant and a rural native. The urban gap is θ + δ. A coefficient inside an interaction is a conditional effect, not an average one.
Also here: DSE 2014 Q47, the two complementary dummies without a constant, which gives the two group means and is the same as separate regressions (the “trap” version, with a constant as well, fails); DSE 2015 Q42, where the gap is most precise with an equal split because Var = σ²(1 ÷ n₁ + 1 ÷ n₂) is smallest at n₁ = n₂; DSE 2011 Q38, where one dummy tests a gender gap after controls; and DSE 2016 Q06, the kinked Engel curve, whose false option is the one that calls it a standard common-intercept formulation, when the term (X − X*)D makes the two segments meet at X*. Lesson 5 covers each.
05
Part 4
Functional form and units
The disguise: a fitted quadratic, or a variable “measured in decades instead of years”. The tools: the slope of a quadratic is b + 2cx, so with c < 0 the effect falls throughout, stays positive until −b ÷ 2c and then turns; and a variable in bigger units has a proportionally bigger coefficient.
Delhi School 2012
ŵage = 3.73 + 0.298 exper − 0.0061 exper², from 500 observations. What does the equation imply?
1
Differentiate.
The marginal return to experience is 0.298 − 0.0122 exper.
2
Read it.
It starts at 0.298 and falls by 0.0122 for each extra year, so it is strictly decreasing everywhere. It is positive until exper = 0.298 ÷ 0.0122 = 24.4 years, then negative.
Answer
(B) Returns to experience are strictly diminishing. Option A confuses a positive effect with an increasing one. Both coefficients are significant (t = 7.3 and −6.8), so D is false.
In the home-sales question (DSE 2019 Q39), age in decades is age ÷ 10, so its coefficient is ten times larger: 0.090 × 10 = 0.900. The official key printed with the paper marks 0.009, which has the units backwards: a larger unit gets a larger coefficient. The platform stores 0.900 and flags the conflict. Lesson 6 has the rule, and it is a good habit to check any such answer against a one-line example.
06
Part 5
Omitted, irrelevant and mismeasured variables
The disguise: a researcher leaves a variable out (or puts a useless one in) and you are asked about bias, variance or what two coefficients reveal. The tools: the short-regression slope equals the long one plus β₂δ; an irrelevant variable costs variance, not bias; and a wrong functional form is an omitted term.
The omitted-variable identity
b1short=b1+b2δ
b_short is the slope on x₁ without x₂, b₁ and b₂ are the long regression's slopes, and δ is the slope of x₂ on x₁. It holds exactly in every sample.
Delhi School 2015
Model A (study hours S and ability A) gives a coefficient on S of 7.1 and on A of 1.9. Model B (S alone) gives 2.1 on S. What does this suggest?
δ is the slope of the omitted variable (ability) on the included one (study hours): negative. Students of lower ability study more.
Answer
(B) Students with lower ability spend more time studying. Leaving ability out makes study look less effective (2.1 instead of 7.1) because the two are negatively related.
The same identity decides DSE 2011 Q39 (an omitted complement, a₂ > 0 and positive δ: an upward bias) and DSE 2014 Q50 (the wrong model has a larger error variance estimate in expectation, E[σ̂²v] ≥ σ²u). DSE 2015 Q45 and DSE 2018 Q28 test the other direction: an irrelevant variable leaves the estimates unbiased and raises their variances. DSE 2016 Q09 fits a line to a quadratic cost curve: the marginal cost is biased, and the residuals follow a pattern (a U-shape against output) that looks like autocorrelation if the data are ordered by output. Lesson 7 has the details.
07
Part 6
Multicollinearity and redundant regressors
The disguise: an equation whose regressors include a combination of the others; or a regression with a high R², a significant F and no significant t. The tools: perfect collinearity means only some combinations of coefficients are identified; near collinearity inflates variances but never biases; and low pairwise correlations do not rule out collinearity among three or more variables.
Delhi School 2011
Y = a₀ + a₁X₁ + a₂X₂ + a₃(X₂ − X₁) + a₄X₁X₂ + u is estimated by OLS. Which parameters can be estimated?
OLS can estimate the coefficient on X₁ (a₁ − a₃) and on X₂ (a₂ + a₃), but not a₁, a₂ and a₃ one by one: the third regressor is an exact combination of the first two.
3
The other terms.
The constant a₀ and the product term a₄ (X₁X₂ is a different, non-linear variable) are separately identified.
Answer
(B) a₀ and a₄ can be estimated, a₁, a₂ and a₃ cannot. The same arithmetic is the dummy-variable trap.
DSE 2012 Q10 asks which is not an indicator of multicollinearity: bias in the coefficients, since collinearity inflates variances and leaves the estimates unbiased. DSE 2016 Q08 has four low pairwise correlations and still a collinearity pattern (high R², significant F, no significant t); the false statement says the coefficients are biased because the correlations are small, when neither the small correlations nor the collinearity creates bias. See lesson 8.
08
Part 7
Heteroscedasticity
The disguise: an error variance that depends on a variable, and a question on what OLS does or how to test. The tools: unbiasedness needs only E(u | x) = 0, so the coefficients stay unbiased; the usual standard errors assume constant variance, so they are wrong; White’s auxiliary regression takes the squared residuals on the regressors, their squares and cross-products.
Delhi School 2018
y = α₀ + α₁x₁ + α₂x₂ + u. What is the most appropriate auxiliary regression for White’s test?
1
What the test explains.
The squared residuals u², since heteroscedasticity is about the size of the errors, not their sign.
2
What it explains them with.
The regressors, their squares and their cross-product, so that any smooth dependence of the variance on x₁ and x₂ is caught: x₁, x₂, x₁², x₂², x₁x₂.
3
Rule out the rest.
Regressions on lagged residuals (B and D) are tests for autocorrelation. Option C lacks the cross-product, which is part of the test.
Answer
(A) u² on a constant, x₁, x₂, x₁², x₂² and x₁x₂.
09
Drill
Which technique?
The hardest step in the exam is the first: recognising which technique a question is inviting. Seven situations, pick the opening move.
Which technique? · 1 of 7
You regress Y on X1 and X2, and also on X1 and the sum X1 + X2. What is the first thing to do?
The pattern
Every hard question here collapses to a line or two once the right object is on the page: a rewritten regression, a t ratio, a group mean, a substitution, the identity b_short = b_long + β₂δ, a collected term, an assumption you have to restore. The difficulty is almost always in choosing the object, not in the arithmetic.
Watch out for
The mistakes examiners are fishing for
Re-estimating what can be rewritten. If two sets of regressors span the same space, the fit is the same and the coefficients are linear functions of each other.
Believing a statement is generally true because it is true with an intercept. The residual facts, the mean square error and R² all change in a regression through the origin.
Reading a dummy coefficient out of context. Inside an interaction it is a conditional gap, and under a recoding it changes.
Mixing up bias and variance. Collinearity, an irrelevant variable and heteroscedasticity (for the coefficients) cost precision, not unbiasedness. An omitted relevant variable and a wrong functional form cost bias.
10
Revise
The lesson on one screen
The lesson on one screen
Reparametrise
A regression on combinations of the regressors is the same fit: Y on X₁ and X₁ + X₂ gives c₁ = b₁ − b₂ and c₂ = b₂. Residual facts: orthogonal to every regressor; Y on e has R² = 1 − R².
A coefficient's variance
σ² ÷ [SST_j(1 − R_j²)]: raised by a smaller n, less spread in x_j, more noise, more collinearity.
From a table
t = b ÷ se. Adjusted R² = 1 − (1 − R²)(n − 1) ÷ (n − k − 1). F to add a variable = [(SSE_R − SSE_UR) ÷ q] ÷ [SSE_UR ÷ df]. Standardised effect = b s_x ÷ s_y.
Dummy regressions
A single dummy fits two means; ESS = n₁n₂ ÷ n × gap². Recoding 0/1 as −1/1: intercept + d ÷ 2, dummy d ÷ 2. Inside an interaction a coefficient is a conditional gap.
Form and units
Quadratic slope b + 2cx, turning point −b ÷ 2c. A variable in bigger units has a bigger coefficient.
Omitted variables
b_short = b_long + b₂δ. An omitted relevant variable biases; an irrelevant one only inflates variance.
Collinearity
Redundant combinations: only the surviving combinations are identified. Near collinearity inflates variances and never biases.
Heteroscedasticity
Coefficients unbiased, usual standard errors wrong. White: u² on x, x², cross-products.
11
Practice
Check yourself
0 of 13 correct so far
Compute
Reparametrising a regression
Y is regressed on X₁ and X₂ with coefficients b₁ = 3 and b₂ = 2. If Y were regressed on X₁ and X₁ + X₂ instead, what would the coefficient on X₁ be?
A standardised effect
A coefficient is 0.8, the regressor has standard deviation 3 and the dependent variable has standard deviation 12. By how many standard deviations of y does y rise for a one standard deviation rise in the regressor?
Explained sum of squares from a dummy
Average pay is 400 for 120 men and 360 for 80 women. A regression of pay on a gender dummy is run. Find the explained sum of squares.
Recoding a dummy
y = 8 + 2x + 6D with D = 0 for one group and 1 for the other. If D were coded −1 and +1, what would the new intercept be?
What the omitted variable reveals
Regressing y on x₁ alone gives a slope of 3.0. Adding x₂ moves the slope on x₁ to 5.0, and the coefficient on x₂ is 4. Find δ, the slope of x₂ on x₁.
An adjusted R²
A regression with 5 slopes and 51 observations has R² = 0.6. Find the adjusted R².
Adding a variable
Adding one variable to a regression on 64 observations (the larger model has 4 slopes) cuts the residual sum of squares from 200 to 180. Find the F statistic for the added variable.
A quadratic's peak
wage = 2 + 0.4 exper − 0.01 exper². At how many years of experience is wage highest?
Quick questions
1Regress Y on a constant and the OLS residuals e from another regression of Y on a constant and X. The R² is
2Which is NOT a consequence of including an irrelevant variable?
3Which regression shows the gap between two groups most precisely, for a fixed total sample of 200?
4Which statement about a regression through the origin is true?
5Heteroscedasticity linked to a variable outside the model, and related to the regressor, leaves OLS coefficients
12
Real questions
The DSE sets
Seven sets, one for each technique above, with all 28 DSE econometrics questions above the easy level. They are open to you whether or not you have worked through the lessons, and each is graded at the end. The easy DSE questions sit in the lessons that teach them.
Part 1 · from Lessons 1 and 2
The algebra of least squares
What is true of the residuals and fitted values of every OLS fit, reparametrising a regression, and what moves the variance of one coefficient.
A standardised effect, whether adding a variable improves the fit, the significance of single coefficients in a home-sales regression, and an explained sum of squares from a dummy regression.
Testing a gender gap with a dummy, a regression on two complementary dummies with no constant, the precision of a gap, recoding a dummy as minus one and plus one, the meaning of a coefficient inside an interaction, and a kinked Engel curve.
The sign of an omitted-variable bias, what an irrelevant variable costs, a linear function fitted to a quadratic, and what the two estimates of a coefficient reveal about the variable left out.
An equation with a redundant combination of regressors (what can still be estimated), the indicators of multicollinearity, and the case of low pairwise correlations with a high R² and insignificant coefficients.
✦These are questions from the TestStop bank. A free account answers 10 a day, each with its worked solution; All-Access opens every set with no daily limit.