The Delhi School of Economics entrance sets the hardest descriptive-statistics questions of any Indian economics exam. They rarely hand you data. They hand you sums, symbols or a few summary figures, and expect you to see what the algebra gives. This lesson teaches the handful of techniques behind them, then gives you every DSE question above the easy level, 32 in all, in five sets.
You regress Y on X by OLS and get fitted values Ŷ. You then regress Y on Ŷ. What is the estimated coefficient of Ŷ: the intercept α̂, the slope β̂, zero, or one?
Questions in the other exams ask you to apply a formula. A hard DSE question asks you to find the formula. Look at how they are phrased: a mean and a variance and two corrected entries; a sum of squares and a standard deviation, but no mean; the equations of two regression lines; a distribution function that lies to the right of another. Five habits cover almost all of them.
Keep sums, not data. A mean is Σx ÷ n and a variance is Σx² ÷ n − x̄². If you are given those, you hold the sums, and any change to the data is a change to the sums.
Work in symbols. When the numbers are letters, keep them letters. Orderings, signs and cancellations show up in algebra that arithmetic hides.
Look for what cancels. Shared terms, constants in a shifted variable, and a divisor that appears top and bottom.
Ask what is invariant. Changing units, shifting, swapping variables: some quantities survive (r, R², a t-ratio) and some do not (a slope, an SSE).
Test the extremes. What does the formula give at r = 0, at r = ±1, with one observation, with all values equal? An option that fails an extreme case is wrong.
Each section below takes one family of questions. Every worked question is a real DSE paper question; the full sets are at the end.
02
Part 1
Averages: symbols, class marks and logs
These questions test whether you have understood what an average is, not whether you can compute one. Four typical forms:
Summation algebra. Simplify an expression with Σ signs, using Σc = nc, Σ(x − y) = Σx − Σy and Σx = nx̄.
An average from symbols. Compare a mean and a median when the values are p, q, p + q and q − p.
Grouped data. Use class marks for the mean (the Gymkhana Club weights) and the cumulative frequency for the median class (the household expenditure table).
Logs. The arithmetic mean of the logs is the log of the geometric mean (Lesson 3), which is why wage regressions in logs describe geometric averages.
DSE 2005 · advanced
Provided c ≠ 0, simplify [Σ(c − xᵢ) − Σ(c yᵢ − xᵢ)] ÷ c.
n − nȳ. Nothing about the xᵢ survives: the algebra decided that before any number was needed.
DSE 2017 · advanced
If real numbers p and q satisfy 0 < q < p, compare the mean and the median of the four numbers p, q, p + q and q − p.
1
Order them.
q − p is negative. Then q < p < p + q. So the order is q − p, q, p, p + q.
2
Median.
The middle two are q and p, so the median is (p + q) ÷ 2.
3
Mean.
(p + q + p + q + q − p) ÷ 4 = (p + 3q) ÷ 4.
4
Compare.
Mean − median = (p + 3q) ÷ 4 − (2p + 2q) ÷ 4 = (q − p) ÷ 4, which is negative.
Answer
The mean is less than the median. The small outlier q − p drags the mean down while the median ignores how far down it goes.
03
Part 2
Spread: keep the sums, not the data
Typically a question reports a mean and a variance for n values, then says some entries were wrong. You never see the data. Do not try to rebuild it. Convert what you are given to Σx and Σx², patch the few wrong terms and convert back.
DSE 2004 · advanced
Ten outcomes were recorded with sample mean 0 and sample variance 4. One outcome recorded as −5 should have been −6, and one recorded as 11 should have been 12. What is the correct variance?
1
Sums as recorded.
Σx = 10 × 0 = 0. Σx² = 10 × (4 + 0²) = 40, taking the variance as Σx² ÷ n − x̄².
2
Patch the sum.
−5 becomes −6 (−1) and 11 becomes 12 (+1). Σx stays 0, so the mean stays 0.
3
Patch the sum of squares.
Remove 25 and 121, add 36 and 144: 40 − 25 − 121 + 36 + 144 = 74.
4
Variance.
74 ÷ 10 − 0² = 7.4.
Answer
7.4. The paper calls 4 the “sample variance” but the option that matches is the one that divides by n. Dividing by n − 1 instead gives Σx² = 36, corrected 70, and 70 ÷ 9 = 7.78, which is not among the options. When the paper’s convention is unclear, test which divisor lands on an option.
The same sums-first move recovers a missing mean. The 2009 question about passengers without tickets gives Σx² = 2,000, n = 20 and σ = 6, and no mean. From σ² = Σx² ÷ n − x̄², 36 = 100 − x̄², so x̄ = 8: the fine is ₹8 each (Lesson 4).
04
Part 3
Correlation: only the shared part survives
Covariance is linear in each of its two arguments. So the covariance of two sums is the sum of all the cross covariances, and when the underlying variables are uncorrelated, nearly all of them vanish. What is left is exactly the part the two sums share.
DSE 2005 · advanced
X, Y and Z are uncorrelated with standard deviations 5, 12 and 9. Let U = X + Y and V = Y + Z. Find the correlation between U and V.
1
Covariance.
Cov(U, V) = Cov(X,Y) + Cov(X,Z) + Cov(Y,Y) + Cov(Y,Z). Three are zero by assumption, leaving Var(Y) = 144.
48/65 ≈ 0.74. The same pattern with three uncorrelated variables of equal variance gives a correlation of 1/2 between X₁ + X₂ and X₁ + X₃ (DSE 2021): half of each sum is the shared X₁.
The other correlation questions test the converse trap. Independent variables are always uncorrelated, but the reverse fails. If X is symmetric about zero, such as a uniform on [−1, 1] or a variable taking −1, 0, 1 with equal probability, then Cov(X, X²) = E[X³] − E[X]E[X²] = 0 although X² is a function of X. They are uncorrelated but dependent (DSE 2010, DSE 2012).
05
Part 4
Regression: algebra on five numbers
A simple regression is fixed by five numbers: x̄, ȳ, σₓ, σᵧ and r. Give the examiner any three of the five and they can ask for the rest. So the first move on every regression question is to write down which of the five you have, and then:
byx=rσXσY,bxy=rσYσX,a=yˉ−bxˉ,R2=r2
DSE 2009 · advanced
ΣXY = 350, ΣX = 50, ΣY = 60, N = 10, V(X) = 4 and V(Y) = 9. Find the correlation coefficient and the two regression slopes.
1
Means.
X̄ = 5 and Ȳ = 6.
2
Covariance.
ΣXY ÷ N − X̄Ȳ = 35 − 30 = 5.
3
Correlation.
5 ÷ (2 × 3) = 5/6.
4
Slopes.
b_yx = 5 ÷ 4 = 5/4 and b_xy = 5 ÷ 9 = 5/9. Check: their product is 25/36 = r².
Answer
5/6, 5/4 and 5/9. The 2008 and 2012 versions of the same data ask for “a one unit change in X is associated with a 1.25 unit change in Y”, which is b_yx, and then an approximation of 5/9 as 0.6.
DSE 2016 · advanced
From 101 classes, TP-hat = 96.4 − 1.12 CS with R² = 0.1 and standard error of the regression 5. Find the sample variance of test percentages.
1
Residual sum of squares.
The standard error of the regression is √(SSE ÷ (n − 2)) = 5, so SSE = 99 × 25 = 2,475.
27.5. Notice the two different degrees of freedom: n − 2 for the standard error of the regression, n − 1 for the variance of y.
DSE 2021 · advanced
Run OLS of Y on X and get fitted values Ŷ. Then regress Y on Ŷ. What is the coefficient γ̂ of Ŷ?
1
Split Y.
Y = Ŷ + e, where e is the residual. By construction e has mean zero and is uncorrelated with the regressor X, so it is uncorrelated with Ŷ, which is a linear function of X.
1, and the intercept is 0, because Ŷ has the same mean as Y. The fitted values are already the best linear predictor of Y, so no rescaling of them helps.
The rest of the regression questions are one-line facts if you ask which quantities are invariant:
Rescaling. If Y* = w₁Y and X* = w₂X, the slope becomes (w₁ ÷ w₂)b, the intercept w₁a, the variance of the slope (w₁ ÷ w₂)² times its old value, and R² does not change (DSE 2012, DSE 2016). In a log-log model, dividing the price by 1,000 changes the intercept by β ln 1,000 and leaves the elasticity β alone (DSE 2013).
R² equals r² only with an intercept (DSE 2014).
Reverse regression. Regressing x on y gives a different slope, but the same t-ratio and the same R² (DSE 2014).
R² is not comparable between models with different dependent variables, such as demand per household and demand per head (DSE 2012).
Equal variances. If σₓ = σᵧ and 0 < ρ < 1, both OLS slopes equal ρ, so both are below 1 (DSE 2020).
Conditional mean. The estimate of the mean of y given x is ȳ + b(x − x̄), which depends on x, so “the mean of y” is not the answer (DSE 2018).
Log-level. In ln Y = 1.2 + 0.5X a one-unit rise in X goes with about a 50% rise in Y. The exact figure is e0.5 − 1 = 64.9%, and the approximation gets worse as the slope grows (DSE 2011).
06
Part 5
Index numbers: the tests and the chain
Three questions from 2006 and 2008 ask for a Laspeyres index (115.3, worked in Lesson 8), for the properties of an ideal index, and for a chain-base index. The last two take care.
DSE 2008 · advanced
Which statements about ideal price indices are true? S1: the index should be invariant to the base, P_rs · P_sr = 1. S2: an index satisfying circularity, P_rs · P_st = P_rt, need not satisfy S1. S3: if all prices change in the same proportion λ, the index should equal λ. S4: changing the units of prices, but not of the quantity weights, should not affect the index.
1
S1.
This is the time reversal test. True.
2
S2.
Set t = r in circularity: P_rs · P_sr = P_rr = 1. So circularity implies S1. S2 is false.
3
S3.
This is the proportionality test: if every price is multiplied by λ, any sensible index is λ. True.
4
S4.
If prices are re-expressed in new units but the quantities are not, each good’s weight changes, and Laspeyres changes with it. Units tests require the quantities to be rescaled to match. False.
Answer
S1 and S3. Circularity is the strongest requirement: it contains time reversal as a special case, and only chain-consistent indices have it.
DSE 2008 · advanced
India’s exports of jute (quantity in ‘000 t: 871, 706, 724, 627; price: 202, 320, 311, 302) and tea (quantity 199, 179, 214, 288; price 577, 767, 884, 799) for 2000 to 2003. Find the chain-base price indices with 2000 as the base.
148.3, 154.3, 145.1 by exact arithmetic. Option C (148.3, 154.2, 144.9) is the closest of the four: the printed figures come from rounding the links along the way. A chain index multiplies year-on-year links, each priced with the earlier year’s quantities, so it avoids a base that becomes out of date.
07
Drill
Which technique?
In the exam the hardest step is the first: recognising which of the techniques above the question is inviting. Six situations; pick the opening move.
Which technique? · 1 of 5
Ten values have a recorded mean and variance. Two entries are found to be wrong. What is the corrected variance?
The pattern
Every hard question here ends in two or three lines once the right object is on the page: a running sum, a shared covariance term, a signed product of slopes, a reversal product. The difficulty is almost always in choosing the object, not in the arithmetic.
Watch out for
The mistakes examiners are fishing for
Rebuilding data you do not need. A mean and a variance are two sums. Patch them.
Reading a picture of distributions as a statement about people.
Forgetting the signs. r takes its sign from the regression slopes. A reversal product, a covariance and a residual all carry signs.
Dividing by n when the paper means n − 1, or the reverse. Check which divisor lands on an option.
Taking an invariance too far. R² and the t-ratio survive swapping the variables. The slope and the SSE do not.
08
Revise
The lesson on one screen
The lesson on one screen
Five habits
Keep sums, not data. Work in symbols. Look for what cancels. Ask what is invariant. Test the extremes.
Corrections
Turn mean and variance into Σx and Σx². Patch the wrong terms. Convert back, with the paper's divisor.
Shared part
Cov of sums = sum of covariances. For uncorrelated parts only the shared variance survives.
Regression
Five numbers fix everything: x̄, ȳ, σₓ, σᵧ, r. b_yx b_xy = r². Regress Y on Ŷ and the slope is 1.
Invariance
Rescaling: R² and r unchanged. Swapping variables: R² and t unchanged, slope and SSE change. R² = r² needs an intercept.
Index tests
Time reversal P₀₁P₁₀ = 1, factor reversal, proportionality. Circularity implies time reversal. Chain indices multiply year-on-year links.
09
Practice
Check yourself
0 of 12 correct so far
Compute
Summation algebra
n = 10 and ȳ = 0.3. Evaluate [Σ(c − xᵢ) − Σ(c yᵢ − xᵢ)] ÷ c for any c ≠ 0.
Correcting a variance
Twenty values have mean 5 and variance 4 (divisor n). A value recorded as 3 should be 8, and a value recorded as 7 should be 2. Find the corrected variance.
A shared part
X and Y are uncorrelated with standard deviations 3 and 2. Find the correlation between U = X + Y and V = X − Y, to three decimal places.
Regression from summaries
n = 10, ΣX = 40, ΣY = 50, ΣXY = 230, V(X) = 4 and V(Y) = 9. Find the slope of the regression of Y on X.
The correlation, same data
For the data in the previous problem, find the correlation coefficient.
R² and the standard error
A regression on 51 observations has R² = 0.5 and a standard error of the regression of 4. Find the sample variance of y.
A chain index
Year-on-year price links are 110 (year 0 to 1), 105 (year 1 to 2) and 96 (year 2 to 3). Find the chain index for year 3 with year 0 as base, to one decimal place.
Exact against approximate
In ln Y = 1.2 + 0.5X, what is the exact percentage change in Y when X rises by one unit? Two decimal places.
Quick questions
1You regress Y on X, then regress Y on the fitted values from the first regression. The slope of the second is
2X is symmetric about 0. Which is true of X and Y = X²?
3Model 1 explains household demand and Model 2 explains demand per head. Model 2 has the higher R². Which statement is correct?
4You regress x on y instead of y on x. Which of these does not change?
10
Real questions
The DSE sets
All 32 DSE questions above the easy level from this module, grouped by where they come from. Moderate questions come first in each set, then the hard ones. Easy DSE questions are in the lessons they belong to.
Part 1 · from Lessons 1 and 2 and 3
Data and averages
Summation algebra, grouped data, comparing a mean with a median, and the mean of logarithms.
Two slopes and r from summary figures, what changes under rescaling and reversal, R² and the standard error, and regressing Y on its own fitted values.
✦These are questions from the TestStop bank. A free account answers 10 a day, each with its worked solution; All-Access opens every set with no daily limit.