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Questions › DSE › DSE 2009 › Q37
2 marksStatistics › Probability and Bayes' theorem › Addition rule, complements and inclusion-exclusionHardabout 4 min

DSE 2009 Question 37: Probability and Bayes' theorem

Jai and Vijay are taking an exam in statistics with grades A, B, C. Pr⁡(Jai gets B)=0.3\Pr(\text{Jai gets B})=0.3Pr(Jai gets B)=0.3, Pr⁡(Vijay gets B)=0.4\Pr(\text{Vijay gets B})=0.4Pr(Vijay gets B)=0.4, and Pr⁡(neither gets an A, but at least one gets a B)=0.1\Pr(\text{neither gets an A, but at least one gets a B})=0.1Pr(neither gets an A, but at least one gets a B)=0.1. What is the probability that neither gets a C but at least one gets a B?

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Jai and Vijay are taking an exam in statistics with grades A, B, C. Pr (Jai gets B)=0.3, Pr (Vijay gets B)=0.4, and Pr (neither gets an A, but at least one gets a B)=0.1. What is the probability that neither gets a C but at least one gets a B? (A) 0.1 (B) 0.6 (C) 0.8 (D) Insufficient data to answer the question

Probability and Bayes' theorem has come up 190 times in 7 exams since 2004.

What this question tests

This question is on Addition rule, complements and inclusion-exclusion, part of Probability and Bayes' theorem in Statistics.

The probability of at least one of several events, and of none.

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Question from the DSE 2009 paper. Solutions are TestStop's own. Not affiliated with or endorsed by any examination authority.