In a year of 366 days, what is the chance that three persons have different birthdays?
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In a year of 366 days, what is the chance that three persons have different birthdays?
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In a year of 366 days, what is the chance that three persons have different birthdays? (A) 1/(366×366×366) (B) 1/(366×365×364) (C) (365×364)/(366×366) (D) 1-(365×364)/(366×366)
Probability and Bayes' theorem has come up 190 times in 7 exams since 2004.
This question is on Classical probability with dice, cards and coins, part of Probability and Bayes' theorem in Statistics.
Probabilities of equally likely outcomes found by counting.
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Question from the IIT JAM 2026 paper. Solutions are TestStop's own. Not affiliated with or endorsed by any examination authority.