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Questions › DSE › DSE 2009 › Q36
2 marksStatistics › Probability and Bayes' theorem › Addition rule, complements and inclusion-exclusionModerateabout 3 min

DSE 2009 Question 36: Probability and Bayes' theorem

Consider two events A and B with Pr⁡(A)=0.4\Pr(A)=0.4Pr(A)=0.4 and Pr⁡(B)=0.7\Pr(B)=0.7Pr(B)=0.7. The maximum and minimum values of Pr⁡(A∩B)\Pr(A\cap B)Pr(A∩B) respectively are:

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Consider two events A and B with Pr (A)=0.4 and Pr (B)=0.7. The maximum and minimum values of Pr (A∩ B) respectively are: (A) (0.4; 0.1) (B) (0.7; 0.4) (C) (0.7; 0.1) (D) (0.4; 0)

Also written as: Consider two events A and B with Pr (A)=0.4 and Pr (B)=0.7. The maximum and minimum values of Pr (A intersection B) respectively are:

Probability and Bayes' theorem has come up 190 times in 7 exams since 2004.

What this question tests

This question is on Addition rule, complements and inclusion-exclusion, part of Probability and Bayes' theorem in Statistics.

The probability of at least one of several events, and of none.

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Question from the DSE 2009 paper. Solutions are TestStop's own. Not affiliated with or endorsed by any examination authority.