Let A and B be independent events and let , where is probability that event X occurs. Let be probability of joint occurrence of events A and B. Then,
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Let A and B be independent events and let , where is probability that event X occurs. Let be probability of joint occurrence of events A and B. Then,
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Let A and B be independent events and let P(B) ≥ P(B), where P(X) is probability that event X occurs. Let P(AB) be probability of joint occurrence of events A and B. Then, (A) P(B) ≥ P(AB) ≥ P(B) (B) P(AB) ≤ P(B) ≤ P(B) (C) P(AB) ≥ P(B) ≥ P(B) (D) P(AB) = P(B) + P(B)
Also written as: Let A and B be independent events and let P(B) >= P(B), where P(X) is probability that event X occurs. Let P(AB) be probability of joint occurrence of events A and B. Then,
Probability and Bayes' theorem has come up 190 times in 7 exams since 2004.
This question is on Independence, part of Probability and Bayes' theorem in Statistics.
When one event tells you nothing about another, and how it differs from being mutually exclusive.
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Question from the UoH 2014 paper. Solutions are TestStop's own. Not affiliated with or endorsed by any examination authority.