UGC-NET 2024 Question 30: Probability and Bayes' theorem

$A$ and $B$ are two events such that $P(\bar{A})=0.4$ and $P(A \cap B)=0.2$ , then $P(A \cap \bar{B})$ is:

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A and B are two events such that P(Ā)=0.4 and P(A ∩ B)=0.2, then P(A ∩ B̄) is: (A) 0.4 (B) 0.2 (C) 0.6 (D) 0.8

Also written as: A and B are two events such that P(A_bar)=0.4 and P(A intersection B)=0.2, then P(A intersection B_bar) is:

Probability and Bayes' theorem has come up 190 times in 7 exams since 2004.

This question is on Addition rule, complements and inclusion-exclusion, part of Probability and Bayes' theorem in Statistics.

The probability of at least one of several events, and of none.

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A and B are two events such that P(Ā)=0.4 and P(A ∩ B)=0.2, then P(A ∩ B̄) is: (A) 0.4 (B) 0.2 (C) 0.6 (D) 0.8

Also written as: A and B are two events such that P(A_bar)=0.4 and P(A intersection B)=0.2, then P(A intersection B_bar) is:

Probability and Bayes' theorem has come up 190 times in 7 exams since 2004.

Question from the UGC-NET 2024 paper. Solutions are TestStop's own. Not affiliated with or endorsed by any examination authority.