The behaviour of a variable over time is described by (where is the variable denoting time).
Suppose at the initial point in time has a negative value. What happens to the value of over time?
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The behaviour of a variable over time is described by (where is the variable denoting time).
Suppose at the initial point in time has a negative value. What happens to the value of over time?
Tap an option to check your answer.
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The behaviour of a variable x over time is described by dx/dt = x² - x (where t is the variable denoting time). Suppose at the initial point in time x has a negative value. What happens to the value of x over time? (A) Decreases without any bound (B) Increases and approaches 0 over time (C) Increases and approaches 1 over time (D) Increases without any bound
Also written as: The behaviour of a variable x over time is described by dx/dt = x^2 - x (where t is the variable denoting time). Suppose at the initial point in time x has a negative value. What happens to the value of x over time?
Difference and differential equations has come up 20 times in 5 exams since 2014.
This question is on Stability and phase diagrams, part of Difference and differential equations in Mathematics.
Whether solutions settle to an equilibrium and how to read the phase line.
TestStop has 8 past-paper questions on this subtopic.
Question from the JNU SSS 2014 paper. Solutions are TestStop's own. Not affiliated with or endorsed by any examination authority.