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Questions › IIT JAM › IIT JAM 2024 › Q14
2 marks, −0.667Mathematics › Difference and differential equations › First-order differential equationsHardabout 3 min

IIT JAM 2024 Question 14: Difference and differential equations

The solution of the differential equation xy dx−(x2+y2) dy=0, y(0)=1xy\,dx - (x^2 + y^2)\,dy = 0,\ y(0) = 1xydx−(x2+y2)dy=0, y(0)=1 is

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The solution of the differential equation xy dx - (x² + y²) dy = 0, y(0) = 1 is (A) y = e^(x/y) (B) y² = e^(x²/y²) (C) y² = e^(x/y) (D) y = e^(x²/y²)

Also written as: The solution of the differential equation xy dx - (x^2 + y^2) dy = 0, y(0) = 1 is

Difference and differential equations has come up 20 times in 5 exams since 2014.

What this question tests

This question is on First-order differential equations, part of Difference and differential equations in Mathematics.

Solving equations in a function and its first derivative.

TestStop has 7 past-paper questions on this subtopic; the nearest in year are below.

  • IIT JAM 2021 · Q8The differential equation (3x² y + y³) dx + (x³ + 3xy²) dy = 0 is
  • IIT JAM 2021 · Q54Let y(x) > 0 solve dy/dx + y = y². If y(ln 2) = 1/3, then y(ln 3) equals _ (round off to 2 decimal places).
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Question from the IIT JAM 2024 paper. Solutions are TestStop's own. Not affiliated with or endorsed by any examination authority.