Let and . If , then (with the adjoint and the determinant)
Let and . If , then (with the adjoint and the determinant)
Answer: (A) and (C)
The two rows give and . Solving, and , so (statement A) while .
The determinant is , so (C) holds. For a matrix , so (D) is false. The correct statements are (A) and (C).
For a matrix , which here is , not ; assuming it is always positive gives the wrong statement (D).
Let x, y ∈ ℝ and M = [x+y x-y; x-y x+y]. If M[3; 1] = [-1; 3], then (with adj(M) the adjoint and det (M) the determinant) (A) x + y = -3/4 (B) x - y = 3/4 (C) det (M) = -1 (D) det (adj(M)) = 1
Also written as: Let x, y in R and M = [x+y x-y; x-y x+y]. If M[3; 1] = [-1; 3], then (with adj(M) the adjoint and det (M) the determinant)
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This question is on Solving linear systems, part of Matrices, determinants and linear systems in Mathematics.
Finding solutions of simultaneous linear equations by inversion, determinants or elimination.
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