Skip to content
We use only essential cookies to keep you signed in and remember your preferences. See our Cookie Policy.
TestStop
MocksPracticeResourcesIndiaBlogPricing
Sign in
Questions › GATE › GATE 2021 › Q39
2 marksMathematics › Matrices, determinants and linear systems › Solving linear systemsHardabout 5 min

GATE 2021 Question 39: Matrices, determinants and linear systems

Given below is an inter-industry transactions matrix. If final demand for the agriculture sector changes from 150 units to 300 units and for the manufacturing sector changes from 120 units to 200 units, then the output of the agriculture sector should be ______ units (in integer).

Producer \ UserAgricultureManufacturingFinal DemandTotal Output
Agriculture5003501501000
Manufacturing320360120800

Answer and worked solution

Answer: 1870

Step 1 - Compute technical coefficients (aija_{ij}aij​ = input from sector iii used by sector jjj, per unit of sector jjj's output):

aAA=5001000=0.5,aAM=350800=0.4375a_{AA} = \frac{500}{1000}=0.5, \quad a_{AM}=\frac{350}{800}=0.4375aAA​=1000500​=0.5,aAM​=800350​=0.4375 aMA=3201000=0.32,aMM=360800=0.45a_{MA} = \frac{320}{1000}=0.32, \quad a_{MM}=\frac{360}{800}=0.45aMA​=1000320​=0.32,aMM​=800360​=0.45

Step 2 - Set up the balance equations with the NEW final demand (FDA=300FD_A=300FDA​=300, FDM=200FD_M=200FDM​=200):

XA=0.5XA+0.4375XM+300X_A = 0.5X_A + 0.4375X_M + 300XA​=0.5XA​+0.4375XM​+300 XM=0.32XA+0.45XM+200X_M = 0.32X_A + 0.45X_M + 200XM​=0.32XA​+0.45XM​+200

Step 3 - Solve the simultaneous system. From the first equation: 0.5XA=0.4375XM+300⇒XA=0.875XM+6000.5X_A = 0.4375X_M+300 \Rightarrow X_A = 0.875X_M+6000.5XA​=0.4375XM​+300⇒XA​=0.875XM​+600.

Substituting into the second: XM=0.32(0.875XM+600)+0.45XM+200=0.28XM+192+0.45XM+200X_M = 0.32(0.875X_M+600)+0.45X_M+200 = 0.28X_M+192+0.45X_M+200XM​=0.32(0.875XM​+600)+0.45XM​+200=0.28XM​+192+0.45XM​+200

XM−0.73XM=392⇒0.27XM=392⇒XM≈1451.85X_M - 0.73X_M = 392 \Rightarrow 0.27X_M = 392 \Rightarrow X_M \approx 1451.85XM​−0.73XM​=392⇒0.27XM​=392⇒XM​≈1451.85

XA=0.875(1451.85)+600≈1870.37X_A = 0.875(1451.85)+600 \approx 1870.37XA​=0.875(1451.85)+600≈1870.37

Therefore the output of the agriculture sector should be approximately 1870 units (rounded to the nearest integer).

The trap: 2100

Students sometimes assume output should scale proportionally with the final demand change (e.g., agriculture's final demand doubled, so output might naively be assumed to roughly double too), missing that the interdependence between sectors (agriculture needs manufacturing inputs and vice versa) means the actual required output change must come from solving the full simultaneous system, not simple proportional scaling.

Matrices, determinants and linear systems has come up 102 times in 7 exams since 2006.

What this question tests

This question is on Solving linear systems, part of Matrices, determinants and linear systems in Mathematics.

Finding solutions of simultaneous linear equations by inversion, determinants or elimination.

TestStop has 8 past-paper questions on this subtopic; the nearest in year are below.

  • IIT JAM 2021 · Q36Let x, y ∈ ℝ and M = [x+y x-y; x-y x+y]. If M[3; 1] = [-1; 3], then (with adj(M) the adjoint and det (M) the…
Take this paper as a timed mockMore on Solving linear systems

Question from the GATE 2021 paper. Solutions are TestStop's own. Not affiliated with or endorsed by any examination authority.