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Questions › GATE › GATE 2024 › Q50
2 marks, −0.667Statistics › Probability and Bayes' theorem › IndependenceModerateabout 2 min

GATE 2024 Question 50: Probability and Bayes' theorem

Assume the following probabilities for two events, AAA and BBB: P(A)=0.50P(A)=0.50P(A)=0.50, P(B)=0.70P(B)=0.70P(B)=0.70, and P(A∪B)=0.85P(A\cup B)=0.85P(A∪B)=0.85. Then we can conclude that

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Assume the following probabilities for two events, A and B: P(A)=0.50, P(B)=0.70, and P(A∪ B)=0.85. Then we can conclude that (A) A and B are mutually independent (B) A and B are equally likely (C) A and B are not mutually independent (D) A and B are mutually exclusive

Also written as: Assume the following probabilities for two events, A and B: P(A)=0.50, P(B)=0.70, and P(A union B)=0.85. Then we can conclude that

Probability and Bayes' theorem has come up 190 times in 7 exams since 2004.

What this question tests

This question is on Independence, part of Probability and Bayes' theorem in Statistics.

When one event tells you nothing about another, and how it differs from being mutually exclusive.

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