Let be a random variable with the probability density function such that
Then, the variance of is ______ (in integer).
Let be a random variable with the probability density function such that
Then, the variance of is ______ (in integer).
Answer: 1
This density describes a Uniform distribution on the interval : it's constant () over the interval and zero elsewhere. Checking normalization: the interval width is , and , confirming it's a valid density.
For a Uniform distribution, the variance formula is:
Here , , so , and .
Therefore the variance of is 1.
Students sometimes recall the variance formula for a symmetric interval around zero, , as rather than the general Uniform formula — applying actually coincides here by a specific-case shortcut, but a student who instead misremembers the shortcut (e.g. using directly without dividing) could land on 3 instead of 1.
Let X be a random variable with the probability density function f(x) such that f(x) = { 1/2√3 if -√3 < x < √3; 0 otherwise } Then, the variance of X is (in integer).
Also written as: Let X be a random variable with the probability density function f(x) such that f(x) = { 1/2sqrt(3) if -sqrt(3) < x < sqrt(3); 0 otherwise } Then, the variance of X is (in integer).
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This question is on Uniform distributions, part of Random variables and standard distributions in Statistics.
Equally likely outcomes over a finite set or an interval.
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