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Questions › DSE › DSE 2019 › Q1
0 marksMathematics › Sets, relations and functions › Functions: domain, range and compositionModerateabout 2 min

DSE 2019 Question 1: Sets, relations and functions

The range of the function f:ℜ→ℜf:\Re\to\Ref:ℜ→ℜ defined by f(x)=x2+x+2x2+x+1f(x)=\dfrac{x^{2}+x+2}{x^{2}+x+1}f(x)=x2+x+1x2+x+2​ is

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The range of the function f:ℜ→ℜ defined by f(x)=(x²+x+2)/(x²+x+1) is (A) [1/3,8/3] (B) (1,∞) (C) [1,7/3] (D) [1,4/3]

Also written as: The range of the function f: Re -> Re defined by f(x)=(x^2+x+2)/(x^2+x+1) is

Sets, relations and functions has come up 65 times in 6 exams since 2004.

What this question tests

This question is on Functions: domain, range and composition, part of Sets, relations and functions in Mathematics.

What makes a rule a function, its domain and range, composition and graph transformations.

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Question from the DSE 2019 paper. Solutions are TestStop's own. Not affiliated with or endorsed by any examination authority.