Suppose four fair coins are tossed simultaneously. Suppose is the event 'the number of Heads strictly exceeds the number of Tails' and is the event 'the number of Tails strictly exceeds the number of Heads'. What is the probability of the event ?
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Suppose four fair coins are tossed simultaneously. Suppose E is the event 'the number of Heads strictly exceeds the number of Tails' and F is the event 'the number of Tails strictly exceeds the number of Heads'. What is the probability of the event E∪ F? (A) 5/8 (B) 1/2 (C) 3/4 (D) 3/8
Also written as: Suppose four fair coins are tossed simultaneously. Suppose E is the event 'the number of Heads strictly exceeds the number of Tails' and F is the event 'the number of Tails strictly exceeds the number of Heads'. What is the probability of the event E union F?
Probability and Bayes' theorem has come up 190 times in 7 exams since 2004.
This question is on Addition rule, complements and inclusion-exclusion, part of Probability and Bayes' theorem in Statistics.
The probability of at least one of several events, and of none.
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Question from the DSE 2005 paper. Solutions are TestStop's own. Not affiliated with or endorsed by any examination authority.