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Questions › UGC-NET › UGC-NET 2025 › Q37
2 marksStatistics › Descriptive statistics and dispersion › Measures of dispersionModerateabout 1 min

UGC-NET 2025 Question 37: Descriptive statistics and dispersion

Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).

(If X is a given series of observations, and a and b are any two constants, then with regard to Standard Deviation (SD).)

Assertion (A): SD(X+a)=SD(X−b)=SD(X)SD(X+a) = SD(X-b) = SD(X)SD(X+a)=SD(X−b)=SD(X) and SD(aX)=a2⋅SD(X)SD(aX) = a^2 \cdot SD(X)SD(aX)=a2⋅SD(X).

Reason (R): SD is independent of change of origin, but not of scale.

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Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R). (If X is a given series of observations, and a and b are any two constants, then with regard to Standard Deviation (SD).) Assertion (A): SD(X+a) = SD(X-b) = SD(X) and SD(aX) = a² · SD(X). Reason (R): SD is independent of change of origin, but not of scale. (A) Both (A) and (R) are correct and (R) is the correct explanation of (A) (B) Both (A) and (R) are correct but (R) is not the correct explanation of (A) (C) (A) is correct but (R) is not correct (D) (A) is not correct but (R) is correct

Also written as: Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R). (If X is a given series of observations, and a and b are any two constants, then with regard to Standard Deviation (SD).) Assertion (A): SD(X+a) = SD(X-b) = SD(X) and SD(aX) = a^2 * SD(X). Reason (R): SD is independent of change of origin, but not of scale.

Descriptive statistics and dispersion has come up 117 times in 6 exams since 2004.

What this question tests

This question is on Measures of dispersion, part of Descriptive statistics and dispersion in Statistics.

How spread out data are: range, variance, standard deviation and relative measures.

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