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Questions › JNU › JNU SSS 2017 › Q49
5 marksMathematics › Real analysis › Supremum, infimum and epsilon argumentsModerateabout 5 min

JNU SSS 2017 Question 49: Real analysis

aaa and bbb are real numbers. If a<b+εa < b + \varepsilona<b+ε for all real numbers ε>0\varepsilon > 0ε>0, then show that a≤ba \leq ba≤b.

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Plain-text version

a and b are real numbers. If a < b + ε for all real numbers ε > 0, then show that a ≤ b.

Also written as: a and b are real numbers. If a < b + epsilon for all real numbers epsilon > 0, then show that a <= b.

Real analysis has come up 38 times in 5 exams since 2005.

What this question tests

This question is on Supremum, infimum and epsilon arguments, part of Real analysis in Mathematics.

Greatest lower and least upper bounds, and proofs that work with arbitrarily small tolerances.

TestStop has 4 past-paper questions on this subtopic.

Practise Real analysisMore on Supremum, infimum and epsilon arguments

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Question from the JNU SSS 2017 paper. Solutions are TestStop's own. Not affiliated with or endorsed by any examination authority.