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Questions › JNU › JNU SSS 2015 › Q6
1 mark, −0.25Mathematics › Limits, continuity and differentiability › Rules of differentiationModerateabout 1 min

JNU SSS 2015 Question 6: Limits, continuity and differentiability

Let f(x)=(log⁡(x))/xf(x) = (\log (x)) / xf(x)=(log(x))/x, where 0<x<10 < x < 10<x<1. Then for all xxx such that 0<x<10 < x < 10<x<1

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Let f(x) = (log (x)) / x, where 0 < x < 1. Then for all x such that 0 < x < 1 (A) f′(x) < 0 (B) f′(x) > 0 (C) f′(x) > 0, if 0 < x < 0·5 and f′(x) < 0, if 0·5 ≤ x < 1 (D) Can’t say anything about the sign of f′(x)

Limits, continuity and differentiability has come up 122 times in 7 exams since 2006.

What this question tests

This question is on Rules of differentiation, part of Limits, continuity and differentiability in Mathematics.

Finding derivatives with the power, product, quotient and chain rules.

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