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Questions › JNU › JNU SSS 2011 › Q71
1 mark, −0.25Statistics › Descriptive statistics and dispersion › Measures of dispersionEasyabout 1 min

JNU SSS 2011 Question 71: Descriptive statistics and dispersion

The mean of a data set is equal to 10 and its standard deviation is equal to 1. If we add 5 to each data value, then the mean and standard deviation become

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The mean of a data set is equal to 10 and its standard deviation is equal to 1. If we add 5 to each data value, then the mean and standard deviation become (A) mean = 15, standard deviation = 6 (B) mean = 10, standard deviation = 6 (C) mean = 15, standard deviation = 1 (D) mean = 10, standard deviation = 1

Descriptive statistics and dispersion has come up 117 times in 6 exams since 2004.

What this question tests

This question is on Measures of dispersion, part of Descriptive statistics and dispersion in Statistics.

How spread out data are: range, variance, standard deviation and relative measures.

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