Suppose a plant can be used to produce in a day x units of product 1 and y units of product 2 where y=(32−5x)/(10−x), where 32/5≥x≥0. If the unit price of product 1 is twice the unit price of product 2, then to maximize total revenue the number of units of x the plant should be used to produce in a day is
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Suppose a plant can be used to produce in a day x units of product 1 and y units of product 2 where y = (32 - 5x)/(10 - x), where 32/5 ≥ x ≥ 0. If the unit price of product 1 is twice the unit price of product 2, then to maximize total revenue the number of units of x the plant should be used to produce in a day is (A) 4 (B) 5 (C) 6 (D) 6· 4
Also written as: Suppose a plant can be used to produce in a day x units of product 1 and y units of product 2 where y = (32 - 5x)/(10 - x), where 32/5 >= x >= 0. If the unit price of product 1 is twice the unit price of product 2, then to maximize total revenue the number of units of x the plant should be used to produce in a day is
Single-variable optimisation has come up 37 times in 6 exams since 2010.
What this question tests
This question is on Applied optimisation, part of Single-variable optimisation in Mathematics.
Maximising profit, revenue or area and minimising cost or time in applied settings.
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Question from the JNU SSS 2010 paper. Solutions are TestStop's own. Not affiliated with or endorsed by any examination authority.