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Questions › JNU › JNU SIS 2020 › Q27
0 marksMathematics › Constrained optimisation and linear programming › Equality-constrained optimisation and Lagrange multipliersModerateabout 2 min

JNU SIS 2020 Question 27: Constrained optimisation and linear programming

Solve : min y=x1+x2y = x_1 + x_2y=x1​+x2​ subject to 1−x1−x2=01 - \sqrt{x_1} - x_2 = 01−x1​​−x2​=0

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Solve: min y = x₁ + x₂ subject to 1 - √(x₁) - x₂ = 0 (A) x₁* = 1/9, x₂* = 2/3 (B) x₁* = 1/4, x₂* = 1/2 (C) x₁* = 1, x₂* = 0 (D) None of the above

Also written as: Solve: min y = x_1 + x_2 subject to 1 - sqrt(x_1) - x_2 = 0

Constrained optimisation and linear programming has come up 44 times in 7 exams since 2007.

What this question tests

This question is on Equality-constrained optimisation and Lagrange multipliers, part of Constrained optimisation and linear programming in Mathematics.

Optimising a function subject to equality constraints, and what the multiplier means.

TestStop has 14 past-paper questions on this subtopic.

Practise Constrained optimisation and linear programmingMore on Equality-constrained optimisation and Lagrange multipliers

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