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Questions › JNU › JNU SIS 2019 › Q14
0 marksMathematics › Limits, continuity and differentiability › Continuity and discontinuitiesEasyabout 1 min

JNU SIS 2019 Question 14: Limits, continuity and differentiability

Consider the function f(x)=3x−5f(x) = 3x - 5f(x)=3x−5 if x≠1x \neq 1x=1 and f(x)=2f(x) = 2f(x)=2 if x=1x = 1x=1 Choose the correct option

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Consider the function f(x) = 3x - 5 if x ≠ 1 and f(x) = 2 if x = 1 Choose the correct option (A) f(x) is discontinuous at x=1 since it is not defined at x=1 (B) f(x) is continuous at x=1 since the left hand limit is equal to the right hand limit at x=1 (C) f(x) is continuous at x=1 since it is defined at x=1 (D) f(x) is discontinuous at x=1 since lim_(x → 1) f(x) ≠ f(1)

Also written as: Consider the function f(x) = 3x - 5 if x != 1 and f(x) = 2 if x = 1 Choose the correct option

Limits, continuity and differentiability has come up 122 times in 7 exams since 2006.

What this question tests

This question is on Continuity and discontinuities, part of Limits, continuity and differentiability in Mathematics.

When a function is continuous at a point and what kinds of breaks occur.

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Practise Limits, continuity and differentiabilityMore on Continuity and discontinuities

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