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Questions › JNU › JNU SIS 2016 › Q5
2 marks, −1Mathematics › Single-variable optimisation › Applied optimisationModerateabout 2 min

JNU SIS 2016 Question 5: Single-variable optimisation

Determine the point(s) on y=x2+1y = x^2 + 1y=x2+1 that is/are closest to (0,2)(0, 2)(0,2).

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Plain-text version

Determine the point(s) on y = x² + 1 that is/are closest to (0, 2). (A) (0, 1) (B) (-1/√2, 3/2), (1/√2, 3/2) (C) (-2, 5), (2, 5) (D) (-4, 17), (4, 17)

Also written as: Determine the point(s) on y = x^2 + 1 that is/are closest to (0, 2).

Single-variable optimisation has come up 37 times in 6 exams since 2010.

What this question tests

This question is on Applied optimisation, part of Single-variable optimisation in Mathematics.

Maximising profit, revenue or area and minimising cost or time in applied settings.

TestStop has 12 past-paper questions on this subtopic.

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Question from the JNU SIS 2016 paper. Solutions are TestStop's own. Not affiliated with or endorsed by any examination authority.