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Questions › JNU › JNU SIS 2013 › Q9
4 marks, −1Mathematics › Integration and its applications › Indefinite and definite integralsModerateabout 2 min

JNU SIS 2013 Question 9: Integration and its applications

Let f(x)={x+4,x<0x2,0≤x<57,x≥5f(x) = \begin{cases} x + 4, & x < 0 \\ x^2, & 0 \le x < 5 \\ 7, & x \ge 5 \end{cases}f(x)=⎩⎨⎧​x+4,x2,7,​x<00≤x<5x≥5​ The area from x=−6x = -6x=−6 to x=8x = 8x=8 under the graph f(x)f(x)f(x) is

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Let f(x) = { x + 4, x < 0; x², 0 ≤ x < 5; 7, x ≥ 5 } The area from x = -6 to x = 8 under the graph f(x) is (A) 130/3 (B) 206/3 (C) 206 (D) 106

Also written as: Let f(x) = { x + 4, x < 0; x^2, 0 <= x < 5; 7, x >= 5 } The area from x = -6 to x = 8 under the graph f(x) is

Integration and its applications has come up 43 times in 6 exams since 2007.

What this question tests

This question is on Indefinite and definite integrals, part of Integration and its applications in Mathematics.

Antiderivatives and areas under curves for standard functions.

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Question from the JNU SIS 2013 paper. Solutions are TestStop's own. Not affiliated with or endorsed by any examination authority.