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Questions › JNU › JNU SIS 2012 › Q15
4 marks, −1Statistics › Random variables and standard distributions › Random variables, PMFs, PDFs and CDFsModerateabout 2 min

JNU SIS 2012 Question 15: Random variables and standard distributions

The probability mass function p(x)p(x)p(x) of a random variable XXX is zero except at points X=0,1,2X = 0, 1, 2X=0,1,2 and 333. If CCC is a constant such that

p(0)=C2, p(1)=2C−3C2, p(2)=2C−1, p(3)=C2p(0) = \frac{C}{2},\ p(1) = 2C - 3C^2,\ p(2) = 2C - 1,\ p(3) = \frac{C}{2}p(0)=2C​, p(1)=2C−3C2, p(2)=2C−1, p(3)=2C​

then

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The probability mass function p(x) of a random variable X is zero except at points X = 0, 1, 2 and 3. If C is a constant such that p(0) = C/2, p(1) = 2C - 3C², p(2) = 2C - 1, p(3) = C/2 then (A) C = 1 and C = 2/3 (B) C = 1 (C) C = 2/3 (D) C = 3/2

Also written as: The probability mass function p(x) of a random variable X is zero except at points X = 0, 1, 2 and 3. If C is a constant such that p(0) = C/2, p(1) = 2C - 3C^2, p(2) = 2C - 1, p(3) = C/2 then

Random variables and standard distributions has come up 173 times in 7 exams since 2005.

What this question tests

This question is on Random variables, PMFs, PDFs and CDFs, part of Random variables and standard distributions in Statistics.

Describing a random variable by its mass, density or distribution function.

TestStop has 33 past-paper questions on this subtopic.

Practise Random variables and standard distributionsMore on Random variables, PMFs, PDFs and CDFs

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Question from the JNU SIS 2012 paper. Solutions are TestStop's own. Not affiliated with or endorsed by any examination authority.