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Questions › JNU › JNU SIS 2012 › Q11
4 marks, −1Mathematics › Limits, continuity and differentiability › Continuity and discontinuitiesEasyabout 1 min

JNU SIS 2012 Question 11: Limits, continuity and differentiability

The function f:R→Rf : R \to Rf:R→R defined by f(x)=x2+2x−3x2−x−2f(x) = \dfrac{x^2 + 2x - 3}{x^2 - x - 2}f(x)=x2−x−2x2+2x−3​ has

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The function f: R → R defined by f(x) = (x² + 2x - 3)/(x² - x - 2) has (A) two points of discontinuity at x = -2 and x = -1 (B) a single point of discontinuity at x = -1 (C) a single point of discontinuity at x = -2 (D) two points of discontinuity at x = 2 and x = -1

Also written as: The function f: R -> R defined by f(x) = (x^2 + 2x - 3)/(x^2 - x - 2) has

Limits, continuity and differentiability has come up 122 times in 7 exams since 2006.

What this question tests

This question is on Continuity and discontinuities, part of Limits, continuity and differentiability in Mathematics.

When a function is continuous at a point and what kinds of breaks occur.

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