Let have pdf for (). For the sample , the Maximum Likelihood Estimator of is
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2 marks, −0.667StatisticsPoint and interval estimationMaximum likelihood estimationModerateabout 2 min
IIT JAM 2023 Question 29: Point and interval estimation
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Let X have pdf f_X(x,λ)=λ e^(-λ x) for x≥0 (λ>0). For the sample 1.75, 2.25, 2.50, 2.75, 3.25, the Maximum Likelihood Estimator of λ is (A) 5/2 (B) 1/5 (C) 5/12 (D) 2/5
Also written as: Let X have pdf f_X(x,lambda)=lambda e^(-lambda x) for x>=0 (lambda>0). For the sample 1.75, 2.25, 2.50, 2.75, 3.25, the Maximum Likelihood Estimator of lambda is
Point and interval estimation has come up 28 times in 6 exams since 2008.
What this question tests
This question is on Maximum likelihood estimation, part of Point and interval estimation in Statistics.
Choosing the parameter value that makes the data most likely.
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