Let be and . Then, on ,
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Let be and . Then, on ,
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Answer: (C)
rises to a single peak at and then falls, so it is single-peaked (quasiconcave) and therefore not quasiconvex.
equals for and for , and is strictly increasing throughout; a monotonic function is quasiconvex. So is not quasiconvex while is, option (C).
Neither function is convex on all of ( has an inflection and is concave on the negative axis), so (A) overstates their curvature; the correct contrast is about quasiconvexity.
Let f, g: ℝ → ℝ be f(x) = xe^(-x) and g(x) = x|x|. Then, on ℝ, (A) both f and g are convex (B) f is convex and g is not convex (C) f is not quasiconvex and g is quasiconvex (D) neither f nor g is quasiconvex
Also written as: Let f, g: R -> R be f(x) = xe^(-x) and g(x) = x|x|. Then, on R,
Concavity, convexity and quasi-concavity has come up 39 times in 6 exams since 2006.
This question is on Quasi-concavity and quasi-convexity, part of Concavity, convexity and quasi-concavity in Mathematics.
The weaker shape conditions defined by upper or lower level sets.
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