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Questions › IIT JAM › IIT JAM 2021 › Q21
2 marks, −0.667Mathematics › Concavity, convexity and quasi-concavity › Quasi-concavity and quasi-convexityHardabout 2 min

IIT JAM 2021 Question 21: Concavity, convexity and quasi-concavity

Let f,g:R→Rf, g: \mathbb{R} \to \mathbb{R}f,g:R→R be f(x)=xe−xf(x) = xe^{-x}f(x)=xe−x and g(x)=x∣x∣g(x) = x|x|g(x)=x∣x∣. Then, on R\mathbb{R}R,

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Answer and worked solution

Answer: (C)

f(x)=xe−xf(x) = xe^{-x}f(x)=xe−x rises to a single peak at x=1x = 1x=1 and then falls, so it is single-peaked (quasiconcave) and therefore not quasiconvex.

g(x)=x∣x∣g(x) = x|x|g(x)=x∣x∣ equals x2x^2x2 for x≥0x \ge 0x≥0 and −x2-x^2−x2 for x<0x < 0x<0, and is strictly increasing throughout; a monotonic function is quasiconvex. So fff is not quasiconvex while ggg is, option (C).

The trap: (A) both fff and ggg are convex

Neither function is convex on all of R\mathbb{R}R (fff has an inflection and ggg is concave on the negative axis), so (A) overstates their curvature; the correct contrast is about quasiconvexity.

Plain-text version

Let f, g: ℝ → ℝ be f(x) = xe^(-x) and g(x) = x|x|. Then, on ℝ, (A) both f and g are convex (B) f is convex and g is not convex (C) f is not quasiconvex and g is quasiconvex (D) neither f nor g is quasiconvex

Also written as: Let f, g: R -> R be f(x) = xe^(-x) and g(x) = x|x|. Then, on R,

Concavity, convexity and quasi-concavity has come up 39 times in 6 exams since 2006.

What this question tests

This question is on Quasi-concavity and quasi-convexity, part of Concavity, convexity and quasi-concavity in Mathematics.

The weaker shape conditions defined by upper or lower level sets.

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