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Questions › DSE › DSE 2020 › Q48
4 marks, −1Mathematics › Sets, relations and functions › One-to-one, onto and invertible functionsHardabout 4 min

DSE 2020 Question 48: Sets, relations and functions

If f,g:R→Rf,g:\mathbb{R}\to\mathbb{R}f,g:R→R are defined by f(x)=0f(x)=0f(x)=0 if xxx is rational and f(x)=xf(x)=xf(x)=x if xxx is irrational, and g(x)=0g(x)=0g(x)=0 if xxx is irrational and g(x)=xg(x)=xg(x)=x if xxx is rational, then h:R→Rh:\mathbb{R}\to\mathbb{R}h:R→R given by h(x)=f(x)−g(x)h(x)=f(x)-g(x)h(x)=f(x)−g(x) is

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If f,g:ℝ→ℝ are defined by f(x)=0 if x is rational and f(x)=x if x is irrational, and g(x)=0 if x is irrational and g(x)=x if x is rational, then h:ℝ→ℝ given by h(x)=f(x)-g(x) is (A) Injective but not surjective (B) Surjective but not injective (C) Neither injective nor surjective (D) Bijective

Also written as: If f,g:R->R are defined by f(x)=0 if x is rational and f(x)=x if x is irrational, and g(x)=0 if x is irrational and g(x)=x if x is rational, then h:R->R given by h(x)=f(x)-g(x) is

Sets, relations and functions has come up 65 times in 6 exams since 2004.

What this question tests

This question is on One-to-one, onto and invertible functions, part of Sets, relations and functions in Mathematics.

Injective, surjective and bijective functions and when an inverse exists.

TestStop has 11 past-paper questions on this subtopic; the nearest in year are below.

  • IIT JAM 2022 · Q13Let f:[0,∞)→ℝ be defined by f(x) = (x+1)/(x+2) for all x in the domain. Then f is
Practise Sets, relations and functionsMore on One-to-one, onto and invertible functions

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Question from the DSE 2020 paper. Solutions are TestStop's own. Not affiliated with or endorsed by any examination authority.