Let be the collection of sets such that for every there are real numbers with . Let be the collection of sets such that for every there are rational numbers with . Then
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Let be the collection of sets such that for every there are real numbers with . Let be the collection of sets such that for every there are rational numbers with . Then
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Let B be the collection of sets E⊆ℝ such that for every x∈ E there are real numbers a<b with x∈(a,b)⊆ E. Let C be the collection of sets E⊆ℝ such that for every x∈ E there are rational numbers a<b with x∈(a,b)⊆ E. Then (A) B⊂C and B≠C (B) C⊂B and B≠C (C) B=C (D) Neither B⊂C nor C⊂B
Also written as: Let B be the collection of sets E subseteq R such that for every x in E there are real numbers a<b with x in (a,b) subseteq E. Let C be the collection of sets E subseteq R such that for every x in E there are rational numbers a<b with x in (a,b) subseteq E. Then
Real analysis has come up 38 times in 5 exams since 2005.
This question is on Topology of the real line: open, closed and compact sets, part of Real analysis in Mathematics.
Which sets are open, closed or compact and how unions and intersections behave.
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Question from the DSE 2020 paper. Solutions are TestStop's own. Not affiliated with or endorsed by any examination authority.