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Questions › DSE › DSE 2015 › Q40
2 marks, −0.666666666666667Mathematics › Sets, relations and functions › Cardinality and countabilityModerateabout 3 min

DSE 2015 Question 40: Sets, relations and functions

Let N={1,2,3,… }\mathcal{N}=\{1,2,3,\dots\}N={1,2,3,…}. Suppose there is a bijection between N\mathcal{N}N and a set XXX, and also a bijection between N\mathcal{N}N and a set YYY. Then

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Let N={1,2,3,…}. Suppose there is a bijection between N and a set X, and also a bijection between N and a set Y. Then (A) there is a bijection between N and X∪ Y (B) there is a bijection between N and X∩ Y (C) there is no bijection between N and X∩ Y (D) there is no bijection between N and X∪ Y

Also written as: Let N={1,2,3,...}. Suppose there is a bijection between N and a set X, and also a bijection between N and a set Y. Then

Sets, relations and functions has come up 65 times in 6 exams since 2004.

What this question tests

This question is on Cardinality and countability, part of Sets, relations and functions in Mathematics.

Comparing the size of sets, including finite, countable and uncountable sets.

TestStop has 6 past-paper questions on this subtopic.

Practise Sets, relations and functionsMore on Cardinality and countability

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Question from the DSE 2015 paper. Solutions are TestStop's own. Not affiliated with or endorsed by any examination authority.